The complete question is this: This figure (Figure 1) shows a container that is sealed at the top by a movable piston. Inside the container is an ideal gas at 1.00 atm, 20.0 ∘C, and 1.00 L. This information will apply to the first three parts of this problem.
A) What will the pressure inside the container become if the piston is moved to the 1.20 L mark while the temperature of the gas is kept constant?
Explanation:
It is given that,
= 1 atm, 
= 1 L
= ? , 
= 1.20 L
As the temperature is constant. Hence, find the value of as follows.
= 
= 
= 0.833 atm
Thus, we can conclude that the pressure inside the container is 0.833 atm.
Answer:
The geosphere consists of the solid Earth and the atmosphere consists of the gaseous components in the air. Thus, the answer is C.
Explanation:
Answer:
10000N
Explanation:
Given parameters:
Mass of the car = 1000kg
Acceleration = 3m/s²
g = 10m/s²
Unknown:
Weight of the car = ?
Solution:
To solve this problem we must understand that weight is the vertical gravitational force that acts on a body.
Weight = mass x acceleration due to gravity
So;
Weight = 1000 x 10 = 10000N
Answer:
Explanation:
The resistance of a wire is given by the equation:
where
is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire
In this problem, we have a wire of platinoid, whose resistivity is
The length of the wire is
L = 7.0 m
And its radius is
, so the cross-sectional area is
Solving for R, we find the resistance of the wire:
The answer is B) wavelength
