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Makovka662 [10]
3 years ago
7

If the radius of the Earth is roughly 3,960 miles, how many times larger is the volume of the Earth than the volume of a ping-po

ng ball? A ping-pong ball has a radius of 0.7441 inches. 1 mile = 5,280 feet.
Physics
1 answer:
kobusy [5.1K]3 years ago
5 0
1) we calculate the volume of the Earth expressed in ft.
Volume of a sphere=(4/3)πr³
3960 miles=3960 miles*(5280 ft/1 mile)=20908800 ft

Volume of the Earth=(4/3)π(20908800 ft)³=(4/3)9.1408*10²¹π ft³

2) we calculate the volume of a ping-pong ball at miles

V=(4/3)π(0.7441 in)³=(4/3)0.412π in³

3)we calculate how many times larger is the volume of the Earh tan the volume of a ping-pòng ball.

(4/3)0.412π in³------------------------ a ping-pong ball.
(4/3)9.1408*10²¹π ft³--------------         x

x=(4/3)9.1408*10²¹π ft³* volume of a ping-pong ball) /(4/3)0.412π in³)=
=2.21865*10²²  ping-pong balls.

Answer: The volume of the Earth is  2.21865*10²²  times larger than  the volume of a ping-pong ball. 







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A 120 kg tackler moving at 3.0 m/s meets head-on (and tackles) a 91 kg halfback moving at 7.5 m/s. What will be their mutual vel
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Explanation:

It is given that,

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We need to find the mutual velocity immediately the collision. It is the case of inelastic collision such that,

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A uniform disk of mass M = 4.9 kg has a radius of 0.12 m and is pivoted so that it rotates freely about its axis. A string wrapp
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(D) 1741.13 J

(E) 725.481 rad

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We have given mass of the disk m = 4.9 kg

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So torque \tau =Fr, here F is force and r is distance

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(C) As the disk starts from rest

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Time t = 4.6 sec

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(E) From second equation of motion

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