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Makovka662 [10]
3 years ago
7

If the radius of the Earth is roughly 3,960 miles, how many times larger is the volume of the Earth than the volume of a ping-po

ng ball? A ping-pong ball has a radius of 0.7441 inches. 1 mile = 5,280 feet.
Physics
1 answer:
kobusy [5.1K]3 years ago
5 0
1) we calculate the volume of the Earth expressed in ft.
Volume of a sphere=(4/3)πr³
3960 miles=3960 miles*(5280 ft/1 mile)=20908800 ft

Volume of the Earth=(4/3)π(20908800 ft)³=(4/3)9.1408*10²¹π ft³

2) we calculate the volume of a ping-pong ball at miles

V=(4/3)π(0.7441 in)³=(4/3)0.412π in³

3)we calculate how many times larger is the volume of the Earh tan the volume of a ping-pòng ball.

(4/3)0.412π in³------------------------ a ping-pong ball.
(4/3)9.1408*10²¹π ft³--------------         x

x=(4/3)9.1408*10²¹π ft³* volume of a ping-pong ball) /(4/3)0.412π in³)=
=2.21865*10²²  ping-pong balls.

Answer: The volume of the Earth is  2.21865*10²²  times larger than  the volume of a ping-pong ball. 







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pav-90 [236]

Answer:

a.After 15 second Mr Comer's speed =  1.7 m/s

b.Distance travelled by Mr.Comer in 15 seconds  =   18.75\ m

Explanation:

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Now we know that V_{i} = 0.8m/s , a = 0.06\ m/s^2 and

t = 15 \ sec

Plugging the values we have.

V_{f} =V_{i} + at

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V_{f} =0.8+ 0.9

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Then Mr.Comer's speed after 15 sec = 1.7ms^-1

b.

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V_{f} ^2-V{i}^2 = 2as

So s = distance covered.

Dividing both sides with 2a we have.

\frac{V_{f} ^2-V{i}^2}{2a} = 2as

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3 years ago
I would love to stretch a wire from our house to the Shop so I can 'call' my husband in for meals. The wire could be tightened t
dezoksy [38]
Note: I'm not sure what do you mean by "weight 0.05 kg/L". I assume it means the mass per unit of length, so it should be "0.05 kg/m".

Solution:
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The wavelength of the standing wave is instead twice the length of the string:
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