A. No polar poplar ..because it starts in the middle and goes out wards
<span>If you overshoot the endpoint in titration of the KHP, an error will happen in your calculations for the molarity of NaOH you are standardizing. For this, a neutralzation reaction happens where amount of acid should be equal to amount of base. Adding more of the base needed to reach the equivalence would mean you have higher volume which will make the calculated concentration of NaOH lesser.</span>
Answer:
76.1g
Explanation:
The balanced equation for this reaction is as follows:
3NaOH + AlCl3 --> Al(OH)3 + 3NaCI
From the above equation, it can be observed that 1 mole of AlCl3 is needed to produce 3 moles of NaCl.
Using the formula below, we convert the mass of NaCl to moles;
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
mole = 100/58.5
mole = 1.71mol of NaCl
Since 1 mole of AlCl3 is needed to produce 3 moles of NaCl.
Then 1.71 moles of NaCl will be produced by 1.71/3 = 0.57mol of AlCl3
Molar mass of AlCl3 = 27 + 35.5(3)
= 27 + 106.5
= 133.5g/mol
Mole = mass/molar mass
Mass = molar mass × mole
Mass = 133.5 × 0.57
Mass = 76.1g
I believe the answer is three bonds. ☺
The answer to this question is -5