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jenyasd209 [6]
3 years ago
9

A solid disk of mass 2 kg and radius 2 m is given a horizontal push of 20N at a point .3 m above its center. a. What is the mini

mum μs between the disk and the floor to allow rolling without slipping?
Physics
1 answer:
Margaret [11]3 years ago
7 0

Answer:

\mu_s=1.0205

Explanation:

Given:

  • mass of solid disk, m=2\ kg
  • radius of disk, r=2\ m
  • force of push applied to disk, F=20\ N
  • distance of application of force from the center, s=0.3\ m

<em>For the condition of no slip the force of  static friction must be greater than the applied force so that there is no skidding between the contact surfaces at the contact point.</em>

\therefore F

where:

f_s = static frictional force

\Rightarrow 20

\Rightarrow 20

\Rightarrow 20

\mu_s>1.0204

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You are riding a bicycle home from school. You average 5 meters per second and you are headed south.
olchik [2.2K]

Answer:

(OD) Velocity

Explanation:

Here, the rider is moving with a steady speed (5 m/s) towards south. In this example, we have magnitude as well as direction. Since velocity is a vector quantity, thus we can determine the velocity of the rider.

5 0
3 years ago
The distance from earth to mars ranges between 780,000,000 km and 380,000,000 km depending on the time of the year. The speed of
ivann1987 [24]

Answer:

The minimum time, t = 21.11 m

Explanation:

Given,

The maximum distance between the Earth and Mars, d = 780,000,000 km

The maximum distance between the Earth and Mars, d = 780,000,000 km

The speed of the light, c = 300,000 km/s

The distance and speed of the object is related using the formula,

                           v = d / t

                            t = d / v

The minimum time it takes for data transmission is when the distance between the Mars and the Earth is at minimum.

Therefore,

                            t = 380,000,000 km / 300,000 km/s

                              = 1266.67 s

                              = 21.11 minutes

Hence, the minimum time it takes for data transmitted by the Mars Surveyor to reach earth, t = 21.11 minutes

6 0
3 years ago
An electron is accelerated from rest through a potential difference. After acceleration the electron has a de Broglie wavelength
Vladimir [108]

Answer:

3x10⁴v

Explanation:

Using

Wavelength= h/ √(2m.Ke)

880nm = 6.6E-34/√ 2.9.1E-31 x me

Ke= 6.6E-34/880nm x 18.2E -31.

5.6E-27/18.2E-31

= 3 x 10⁴ Volts

4 0
3 years ago
Find the work w1 done on the block by the force of magnitude f1 = 95.0 n as the block moves from xi = -5.00 cm to xf = 4.00 cm .
Vlad [161]
<h3><u>Answer;</u></h3>

= 8.55 Joules

<h3><u>Explanation;</u></h3>

Work done is the product of force and the distance moved by an object.

Work done = Force × distance

Force = 95 Newtons

Distance = X2 -X1

               = 4 - (-5)

               = 9 cm

Thus;

work done = 95 × 9/100

                  <u>= 8.55 Joules </u>

5 0
3 years ago
A firecracker in a coconut blows the coconut into three pieces. Twopieces of equal mass fly off south and west, perpendicular to
loris [4]

Answer:

V = 13m/s

North-East (i.e. 45 degree from North)

Explanation:

This question deals with the idea of momentum.

Since the directions of a compass are fixed, we can take south as horizontal and west as vertical. Since both pieces of coconut are of equal mass, then the resultant of the two pieces would be in between South and West and the third piece would be opposite this direction and be in the North-East (i.e. 45 degree from North) direction

To find the speed of the third piece, we first find the speed on the two pieces of the coconut in terms of V_{x} (horizontal component of velocity) and V_{y} (vertical component of velocity)

We have

V_{y} = Velocity in South direction = 18m/s

m_{y} = Mass of piece in South direction = m

V_{x} = Velocity in West direction = 18m/s

m_{x} = Mass of piece in West direction = m

V_{ry} = Velocity of Third Piece in North direction = unknown

V_{rx} = Velocity of Third Piece in East direction = unknown

m = Mass of third piece = 2m

mV_{ry}  = m_{y} V_{y} \\ 2mV_{ry}  = m18\\ V_{ry} = 9

mV_{rx}  = m_{x} V_{x} \\ 2mV_{rx}  = m18\\ V_{rx} = 9

Since we now know the horizontal and vertical component of the velocity of the third piece of coconut we find the resultant velocity. Since we know the direction is North-East, we can imagine a right angled triangle with base of 9 and height 9 and the hypotenuse equal to the resultant velocity .

We can simply apply the Pythagoras theorem and find the hypotenuse

Hypotenuse^{2}  = Height^{2}  + Base^{2} \\ V_{3}^2  = 9^{2} + 9^{2} \\ V = 12.728 m/s

V = 13m/s

6 0
3 years ago
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