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sergeinik [125]
3 years ago
6

As water moves down through the ground, what force is acting against it?

Physics
2 answers:
viktelen [127]3 years ago
5 0
The answer is Capillary action.        apex
Irina18 [472]3 years ago
3 0

Answer:

capillary action

Explanation: It is the ability of liquid to flow in narrow spaces against the gravity and is the result of inter-molecular forces between liquid and the surrounding solid surface. This rising is the result of two opposite forces adhesion and cohesion. Capillarity is high when adhesion is more than cohesion.

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A ________ detects the speed that a given device can handle and communicates with it at that speed
melisa1 [442]
Switch because look A switch detects the speed that given device can handle and communicates with it at that speed
4 0
3 years ago
PLEASE HELP, LOOK AT PHOTO PLZ!!!
PIT_PIT [208]

Answer:

a) 17 km

b) 9 km

Explanation:

The distance is the length of the path.

A to C: 5 km

B to C: 4 km

C to B: 4 km

B to C: 4 km

Total distance = 5 km + 4 km + 4 km + 4 km = 17 km

Displacement is the difference between the starting point and ending point.

Displacement = 9 km − 0 km = 9 km

3 0
3 years ago
A constant force of 5.00 N acts on a 2.50 kg object for 10.0 s. What are the changes in the object’s momentum and velocity?
dimulka [17.4K]
Hope this answer helps, cause Idk, I might be wrong, but I still, I used the correct formulas, so I might be correct

7 0
2 years ago
22. (I) A car slows down from 28 m/s to rest in a distance of
lidiya [134]

Answer:

a = -8.912 m/s²

Explanation:

Given,

The initial velocity of the car, u = 28 m/s

The final velocity of the car, v = 0

The distance traveled by car, d = 88 m

The velocity displacement relation is given by the formula

                                          v = d/t

∴                                         t = d/v

Substituting in the above values in the given equation

                                           t = 88/28

                                            = 3.142 s

The acceleration is given by the formula

                                         a = (v-u)/t

                                            = (0 - 28)/3.142

                                            = -8.912 m/s²

The negative sign is that the car is decelerating.

Hence, acceleration a = -8.912 m/s²

7 0
3 years ago
A factory worker pushes a 32.0 kgkg crate a distance of 4.0 mm along a level floor at constant velocity by pushing horizontally
Luda [366]

Answer:

a) The force that the worker must apply has a magnitude of 75.317 newtons.

b) The external force does a work of 0.301 joules.

c) The friction force does a work of -0.301 joules.

d) Both normal force and gravity have done a work of 0 joules.

e) The total work done on the crate is 0 joules.

Explanation:

a) As the crate is moving at constant velocity, we know that magnitude of the force done on the crate must be equal to the friction force. Hence, we must use the following formula:

F = \mu\cdot m\cdot g (1)

Where:

F - External force, in newtons.

\mu - Coefficient of kinetic friction, no unit.

m - Mass, in kilograms.

g - Gravity acceleration, in meters per square second.

If we know that \mu = 0.24, m= 32\,kg and g = 9.807\,\frac{m}{s^{2}}, then the external force is:

F = (0.24)\cdot (32\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F = 75.317\,N

The force that the worker must apply has a magnitude of 75.317 newtons.

b) The direction of the force is parallel to the direction of motion. The work done by this force (W_{F}), in joules, is determined by this formula:

W_{F} = F\cdot \Delta s (2)

Where \Delta s is the distance travelled by the crate, in meters.

If we know that F = 75.317\,N and \Delta s = 0.004\,m, then the work done by the force is:

W_{F} = (75.317\,N)\cdot (0.004\,m)

W_{F} = 0.301\,J

The external force does a work of 0.301 joules.

c) The direction of the friction force is antiparallel to the direction of motion. The work done by this force (W_{f}), in joules, is determined by this formula:

W_{f} = -W_{F} (3)

W_{f} = -0.301\,J

The friction force does a work of -0.301 joules.

d) The direction of the normal force is perpendicular to the direction of motion. Therefore, no work is done due to normal force.

W_{N} = 0\,J

Likewise, no work is done by gravity.

W_{g} = 0\,J

Both normal force and gravity have done a work of 0 joules.

e) The total work is the sum of the works done by the external force and the friction force:

W = W_{F}+W_{f}

W = 0.301\,J - 0.301\,J

W = 0\,J

The total work done on the crate is 0 joules.

5 0
2 years ago
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