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blsea [12.9K]
4 years ago
6

A student sets up the following equation to convert a measurement.

Chemistry
1 answer:
Marat540 [252]4 years ago
8 0

Answer:

0.029

Explanation:

Initially, the number the student intends calculating is 29:

 From 29 x \frac{N}{c^{2} m^{2} }

but a submutiple of a thousand was introduced in form of mc²:

  this implies:

     29 x( 1/\frac{1}{1000}) \frac{N}{c^{2} m^{2} }:

to make the expression correct: 29 should be 0.029

 0.029 x ( 1/\frac{1}{1000})   \frac{N}{c^{2} m^{2} }

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*Asap*
ira [324]

Answer:

(a).

order \: of \: A = 2 \\ order \: of \:B  = 0 \\ rate = k[A] {}^{2} [B]

(b)

0.32 \times  {10}^{ - 3}  = k {(0.12)}^{2} (0.15) \\ k = 0.148 \:  {mol}^{ - 2}  {dm}^{6}  {s}^{ - 1}

(c). The rate increases because kinetic energy of reactant molecules increases.

7 0
3 years ago
A 0.2 M carboxylic acid (RCOOH) has a Ka = 1.66x10-6. What is the pH of this solution? Enter to 2 decimal places.
maria [59]

Answer:

3.24

Explanation:

The dissociation equation for the carboxylic acid can be represented as follows:

RCOOH —-> RCOO- + H+

We can use an ICE table to get the value of the concentration of the hydrogen ion. ICE stands for initial, change and equilibrium.

RCOOH RCOO- H+

Initial 0.2 0.0. 0.0

Change -x +x. +x

Equilibrium 0.2-x. x. x

We can now find the value of x as follows:

Ka = [RCOO-][H+]/[RCOOH]

(1.66* 10^-6) = (x * x)/(0.2-x)

(1.66 * 10^-6) (0.2-x) = x^2

x^2 = (3.32* 10^-7) - (1.66*10^-6)x

x^2 + (1.66 * 10^-6)x - (3.32* 10^-7) = 0

Solving the quadratic equation to get x:

x = 0.0005753650094369094 or - 0.0005753650094369094

As concentration cannot be negative, we discard the negative answer

Hence [H+] = 0.0005753650094369094

By definition, pH = -log[H+]

pH = -log(0.0005753650094369094)

pH = 3.24

8 0
3 years ago
A student was traveling to see his grandmother who lives 15 miles north of his home. He started from rest and maintained a pace
AnnZ [28]

Answer:

He traveled at a speed of 4 m/s with a velocity of 4m/s north, and his acceleration changed when stopping for lunch.

Explanation:

Trust me took test got it right!

8 0
3 years ago
Which of the following is an isoelctronic series
Darina [25.2K]
Sir cn you tell me that can we use this formula
3 0
3 years ago
What mass of silver chloride (m = 143.4) will dissolve in 1.00 l of water? the ksp of agcl is 1.8 × 10–10 ?
trapecia [35]
Given that solubility product of AgCl = 1.8 X 10^-10

Dissociation of AgCl can be represented as follows,

AgCl(s)             ↔      Ag+(ag)             +           Cl-(aq)

Let, [Ag+] = [Cl-] = S

∴Ksp = [Ag+][Cl-] = S^2

∴ S = √Ksp = √(1.8 X 10^-10) = 1.34 x 10^-5 mol/dm3

Now, Molarity of solution = \frac{\text{weight of solute}}{\text{Molecular weight X volume of solution (l)}}
              ∴  1.34 x 10^-5     = \frac{\text{weight of AgCl}}{143.4 X 1}
∴ Weight of AgCl present in solution = 1.92 X 10^-3 g

Thus, mass of AgCl that will dissolve in 1l water = 1.92 x 10^-3 g
7 0
3 years ago
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