To finish one orbit it will take 98 x 60 seconds. So; <span>(2 x pi)/(98 x 60) = 1.07 x 10^-3 rad/sec. </span><span>
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Well first of all, since the question deals with the relationship of Charon and Pluto, we don't care about their distance from the sun, because that has no effect on the gravitational forces between them.
All we need is Newton's law of universal gravitation:
Gravitational forces = G m₁ m₂ / D² .
' G ' is the gravitational constant ... 6.67 x 10⁻¹¹ newt-m²/kg²
m₁ = either one of the masses ... 1.31 x 10²² kg (Pluto)
m₂ = the other mass ... 1.55 x 10²¹ kg (Charon)
D = the distance between their centers ... 1.96 x 10⁷ meters
Gravitational forces = G m₁ m₂ / D²
= (6.67 x 10⁻¹¹ newt-m²/kg²)
times (1.31 x 10²² kg) times (1.55 x 10²¹ kg)
divided by (1.96 x 10⁷ meters)²
= (6.67 x 1.31 x 1.55 x 10⁻¹¹ ⁺ ²² ⁺ ²¹ ⁻ ¹⁴) / (1.96)²
= (13.54 x 10¹⁸) / (3.84) = 3.53 x 10¹⁸ newtons .
<span>This is the gravitational force of attraction that Pluto exerts
on Charon. It's also the </span><span>gravitational force of attraction that
Charon exerts on Pluto. The gravitational forces are always
equal and opposite.
</span>
For each revolution, the satellite covers the circumference
of its orbit.
The circumference of a circle is (pi) x (diameter).
Since the satellite is 22,500 miles from the center, that number
is the radius of the circle. The diameter is 45,000 miles.
The circumference is (pi) x (45,000 miles) = 141,372 miles
The satellite's average speed is 141,372 miles per day, or
(141,372 / 24) = 5,890 miles per hour
relative to the center of the Earth.
Answer:
The initial velocity of the gymnast is 8.5 m/s.
Explanation:
We can use the kinematic equation
to figure out the initial velocity 
of the gymnast.
Now, when the gymnast reaches the maximum height, the distance he has traveled is 
, and his velocity is zero; therefore 
.
Thus, we have
Answer:
20 mi
Exp3tanation:
I did the same question in a quizz
