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3 years ago

Do balanced forces change an objects motion

1 answer:

meriva3 years ago

8 0

If the group of all forces acting on an object is balanced,
then the effect of all of them is the same as if there were
no forces at all on the object. In that case, the object
continues moving in a straight line at a constant speed.

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7. A 1.0 kg metal head of a geology hammer strikes a solid rock with a velocity of 5.0 m/s. Assuming all the energy is retained

marta [7]

The increase in temperature of the metal hammer is 0.028 ⁰C.

The given parameters:

mass of the metal hammer, m = 1.0 kg
speed of the hammer, v = 5.0 m/s
specific heat capacity of iron, 450 J/kg⁰C

The increase in temperature of the metal hammer is calculated as follows;

$Q = K.E\\\\mc \Delta T = \frac{1}{2} mv^2\\\\\Delta T = \frac{v^2}{2 c}$

where;

c is the specific heat capacity of the metal hammer

Assuming the metal hammer is iron, c = 450 J/kg⁰C

$\Delta T = \frac{5^2}{2 \times 450} \\\\\Delta T = 0.028 \ ^0C$

Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.

Learn more about heat capacity here: brainly.com/question/16559442

8 0

3 years ago

2. What would be the acceleration of the clown at 5 s? (A) 1.6 m/s2 (B) 8.0 m/s2 (C) 2.0 m/s2 (D) 3.4 m/s2 3. After 12 seconds,

Neko [114]

Is there an image that goes with this question?

7 0

2 years ago

A Hammer is an example of a _____________ Machine

Nesterboy [21]

A hammer is a type of lever.

6 0

4 years ago

Read 2 more answers

An arrow is shot at an initial velocity of 224 ft/sec from a height of 44 feet, ay what time will the arrow be 824 feet above th

Bingel [31]

The arrow is subject to the constant downward pull of gravity, so its vertical position over time is given by

$y=44\,\mathrm{ft}+\left(224\,\dfrac{\mathrm{ft}}{\mathrm s}\right)t+\dfrac12\left(-32.1\,\dfrac{\mathrm{ft}}{\mathrm s^2}\right)t^2$

We want to find $t$ for which $y=824\,\mathrm{ft}$ . You should find two solutions at $t=6.67\,\mathrm s$ and $t=7.29\,\mathrm s$ .

7 0

4 years ago

How you do this resistor in circuit question?

lawyer [7]

If Resistors are in series= The equivalent is the sum.

E.g R1 and R2 in series, R = R1 + R2.

If in Parallel, equivalent is Product/sum.

E.g If R1 and R2 in parallel, R = (R1*R2)/(R1+R2)

1.) 60 is parallel with 40 and both are then in series with 20.

60//40 = (60*40)/(60+40) = 2400/100 = 24

Now the 24 is in series with the 20

R = 24 + 20 = 44 ohms.

2.) 80 is in series with 40 and both are then in parallel with 40.

Solving the series, R = 80 + 40 =120.

Parallel: 120//40 = (120*40)/(120+40) = 4800/160 = 30
Equivalent Resistance = 30 ohms.

3.) 100 is in parallel with 100 and both are then in series with the parallel of 50 and 50.

The 1st parallel = (100*100)/(100+100) = 10000/200 = 50

The 2nd parallel = (50*50)/(50+50) = 2500/100 = 25.

Solving the series = 50 + 25 =75 ohms.

Cheers.

3 0

4 years ago