Answer:
The charge on the ball bearing 4.507 × 10^-8 C
Explanation:
From Coulomb's law
F = kq1q2/r²
make q2 the subject
q2 = Fr²/kq1
q2 = (1.8×10^-2 × 0.026²) ÷ (9×10^9 × 30×10^-9)
q2 = 4.507 × 10^-8 C
Answer:
10.66mm
Explanation:
Given that the elongation is and Length, and Tensile Strength,, The longitudinal stress can be calculated as:
The value of strain-stress, corresponding to '
Hence, the radius of the specimen is 10.66mm
As we know by Gauss's law that
so for line charge the gaussian surface is cylindrical in shape
so we will have
now by rearranging the terms
so here we will have to find the x component of electric field so it is given by above equation
here x = distance from the wire where we need to find electric field
Answer:
option (A)
Explanation:
The a body having rest mass is mo is moving with velocity v which is of the order of velocity of light in vacuum, so the mass of the body increases. According to the formula
As the velocity increases, the mass m of the body increases. As the velocity of the object is equal to the velocity of light in vacuum, then the mass of the body becomes infinite.