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3 years ago

11

The rocket now has a thruster that malfunctions and is now pushing the rocket in the wrong direction. What is the new net force

on the rocket if it is now accelerating at 12mls²??

2 answers:

DENIUS [597]3 years ago

8 0

From your previous question

Mass=30kg
Acceleration=12m/s^2

$\\ \sf\longmapsto F=ma$

$\\ \sf\longmapsto F=30(12)$

$\\ \sf\longmapsto F=360N$

Lana71 [14]3 years ago

3 0

Answer:

Daddy Dr Dr Dr Dr

Explanation:

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3 years ago

50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the bui

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Answer:

98.13m

Explanation:

Complete question

Daniel is 50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the building

CHECK THE ATTACHMENT

From the figure, using trigonometry

Tan(θ ) = opposite/adjacent

Where Angle (θ )= 63°

Opposite= X = height of the building

Adjacent= 50 m

Then substitute the values we have

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3 years ago

Why can work be thought of as the transfer of energy? Please help it's physics

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3 years ago

Read 2 more answers

A roller coaster is traveling at 13 m/s when it approaches a hill that is 400 m long. Heading down the hill, it accelerates at 4

SIZIF [17.4K]

Answer:

The value is $v = 47 \ m/s$

Explanation:

From the question we are told that

The initial speed of the roller coaster is $u = 13 \ m/s$

The length of the hill is $l = 400 \ m$

The acceleration of the roller coaster is $a=4.0 \ m/s^2$

Generally the acceleration is mathematically represented as

$a = \frac{ v - u}{ t_f - t_i }$

Here $t_i$ is the initial time which is equal to zero

$v_f$ is the final velocity which is mathematically represented as

$v_f = \frac{d}{ t_f}$

So

$a = \frac{ \frac{d}{d_f} - u }{ t_f - t_i}$

$4 = \frac{\frac{400}{ t_f} - 13}{t_f - 0}$

$4 = \frac{400 - 13t_f}{ t_f} * \frac{1}{t_f}$

$4t_f ^2 +13f + 400 =$

Solving this using quadratic formula we obtain

$t_f = 8.5 \ s$

$t_f = -11.8 \ s$

Generally time cannot be negative so

$t_f = 8.5 \ s$

Generally the final velocity is mathematically represented as

$v = \frac{400}{8.5}$

$v = 47 \ m/s$

5 0

3 years ago