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rusak2 [61]
3 years ago
11

The rocket now has a thruster that malfunctions and is now pushing the rocket in the wrong direction. What is the new net force

on the rocket if it is now accelerating at 12mls²??​
Physics
2 answers:
DENIUS [597]3 years ago
8 0

From your previous question

  • Mass=30kg
  • Acceleration=12m/s^2

\\ \sf\longmapsto F=ma

\\ \sf\longmapsto F=30(12)

\\ \sf\longmapsto F=360N

Lana71 [14]3 years ago
3 0

Answer:

Daddy Dr Dr Dr Dr

Explanation:

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If an object that weighs 20 N is lifted from the ground to a
Radda [10]

Answer:

false 20 n x 0.32 m = 6.4 J

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4 years ago
A 2800 kg truck moving at 12 m/s to the right hits a stopped 1100 kg car. What is the combined velocity the moment they stick to
leva [86]

Answer:

The combined velocity is 8.61 m/s.

Explanation:

Given that,

The mass of a truck, m = 2800 kg

Initial speed of truck, u = 12 m/s

The mass of a car, m' = 1100 kg

Initial speed of the car, u' = 0

We need to find the combined velocity the moment they stick together. Let it is V. Using the conservation of momentum.

m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\\\\V=\dfrac{2800\times 12+0}{2800+1100}\\\\V=8.61\ m/s

So, the combined velocity is 8.61 m/s.

5 0
3 years ago
Someone please help me
professor190 [17]
The answer is A. conduction
7 0
3 years ago
What happens when the temperature of a substance decreases significantly?
SIZIF [17.4K]
When temperature decreases the atoms(or molecules) within the substance begin to slow down. 
6 0
3 years ago
Read 2 more answers
A body of mass 25kg, moving at 3 ms per second on a rough horizontal floor brought to rest after sliding through a distance of 2
erastova [34]
You have to solve this by using the equations of motion:
u=3
v=0
s=2.5
a=?
v^2=u^2+2as
0=9+5s
Giving a=-1.8m/s^2

Then using the equation:
F=ma
F is the frictional force as there is no other force acting and its negative as its in the opposite direction to the direction of motion.

-F=25(-1.8)
F=45N

Then use the formula:
F=uR
Where u is the coefficient of friction, R is the normal force and F is the frictional force.

45=u(25g)
45=u(25*10)

Therefore, the coefficient of friction is 0.18

Hope that helps




5 0
4 years ago
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