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3 years ago

11

The rocket now has a thruster that malfunctions and is now pushing the rocket in the wrong direction. What is the new net force

on the rocket if it is now accelerating at 12mls²??

2 answers:

DENIUS [597]3 years ago

8 0

From your previous question

Mass=30kg
Acceleration=12m/s^2

$\\ \sf\longmapsto F=ma$

$\\ \sf\longmapsto F=30(12)$

$\\ \sf\longmapsto F=360N$

Lana71 [14]3 years ago

3 0

Answer:

Daddy Dr Dr Dr Dr

Explanation:

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A projectile is launched at an angle above the

gtnhenbr [62]

The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.

The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.

v = 30 + (-9.81x2)
v = 30 - 19.62
=10.38m/s

Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.

The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.

Combining this together we get:
(1) vx=40m/s and vy=10m/s

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3 years ago

a snail takes 16 minutes 40 seconds to cover a distance of 1 m calculate the average speed of the swimmer

matrenka [14]

The snail’s speed is 0.001042. Hope this helps!

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2 years ago

Read 2 more answers

Why the dogs lays down next to the wood stove? Is it radiation,convection,conduction?

malfutka [58]

Radiation because it radiates the heat in there body therefore making them hot.

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3 years ago

Tim can type 2000 words at a speed of 50 words per minute bobs typing speed is 80 words per minute how much less time did bob ta

Whitepunk [10]

Answer:

15 less mins will be used by Bob

Explanation:

This is because it takes Tim 2000/50= 40mins to type the whole work

While it takes Bob 2000/80= 25 mins

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8 0

3 years ago

A convex thin lens with refractive index of 1.50 has a focal length of 30cm in air. When immersed in a certain transparent liqui

GalinKa [24]

Answer:

$n_l = 1.97$

Explanation:

given data:

refractive index of lens 1.50

focal length in air is 30 cm

focal length in water is -188 cm

Focal length of lens is given as

$\frac{1}{f} =\frac{n_2 -n_1}{n_1} * \left [\frac{1}{r1} -\frac{1}{r2} \right ]$

$\frac{1}{f} =\frac{n_{g} -n_{air}}{n_{air}} * \left [\frac{1}{r1} -\frac{1}{r2} \right ]$

$\frac{1}{f} =\frac{n_{g} -1}{1} * \left [\frac{1}{r1} -\frac{1}{r2} \right ]$

focal length of lens in liquid is

$\frac{1}{f} =\frac{n_{g} -n_{l}}{n_{l}} * \left [\frac{1}{r1} -\frac{1}{r2} \right ]$

$=\frac{n_{g} -n_{l}}{n_{l}} [\frac{1}{(n_{g} - 1) f}$

rearrange fro $n_l$

$n_l = \frac{n_g f_l}{f_l+f(n_g-1)}$

$n_l = \frac{1.50*(-188)}{-188 + 30(1.50 -1)}$

$n_l = 1.97$

7 0

3 years ago