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Flura [38]
3 years ago
14

What are loops of gas on sun that link different parts of sunspot regions together?

Physics
1 answer:
love history [14]3 years ago
7 0
So we want to know what are loops of gas on the Sun that link different parts of sunspot regions together. A large and bright gaseous feature that extends from the surface of the Sun that links different parts of sunspot regions together is called Prominence. They are on the Suns surface in the photosphere and they extend outwards into the Corona. 
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Mass and Weight: What is the mass of an object that experiences a gravitational force of 685 N near Earth's surface where g
11Alexandr11 [23.1K]

Answer:

m = 69.9 kg

Explanation:

The mass and the weight of an object are two different quantities. Mass is basically the amount of matter that is present in a body. It remains same everywhere in the universe and measured in kilograms.

Weight is basically a force. It is the force by which earth attracts everything towards itself. The weight of an object changes from planet to planet, with the change in value of the gravitational acceleration (g).

Therefore, the relation between mass and weight of an object is given by the following formula:

W = mg

m = W/g

where,

m = mass = ?

W = Weight = 685 N

g = 9.8 m/s²

Therefore,

m = (685 N)/(9.8 m/s²)

<u>m = 69.9 kg</u>

4 0
3 years ago
In a certain region of space, the electric potential is V(x,y,z)=Axy-Bx^2+Cy , where A,B , and C are positive constants.a) Calcu
laiz [17]

Answer:

a)  Eₓ = - A y + 2B x , b)  Ey = -Ax –C , c) Ez = 0 , d) The correct answer is 3

Explanation:

The electric field and the electric power are related

                    E = - dV / ds

a) Let's find the electric field on the x axis

                  Eₓ = - dV / dx

                  dV / dx = A y - B 2x

                  Eₓ = - A y + 2B x

b) calculate the electric field on the y-axis

                Ey = - dV / dy

                dV / dy = A x + C

                Ey = -Ax –C

c) the electric field on the z axis

              dv / dz = 0

              Ez = 0

.d) at which point the electric field is zero

Since the electric field is a vector quantity all components must be zero

X axis

              0 = = - A y + 2B x

              y = 2B / A x

Axis y

             0 = -Ax –C

              .x = -C / A

We substitute this value in the previous equation

             .y = 2B / A (-C / A)

             .y = 2 B C / A2

The correct answer is 3

6 0
3 years ago
In a circuit, a variable resistor is to be connected across a potential difference of 60 volts to allow the current to be adjust
sweet [91]

Answer:

600 and 1500 [ohm

Explanation:

To solve this problem we must use ohm's law, which tells us that the voltage is the product of the current by the resistance, so we have:

V = I*R

where:

V = voltage [V]

I = current [amp]

R = resistance [ohm]

<u>Therefore:</u>

R = V/I

R1 = 60/(40*10^-3) = 1500 [ohm]

R2 = 60/(100*10^-3) = 600 [ohm]

So the resistance should be among 600 and 1500 [ohm]

4 0
3 years ago
Create a series circuit with a 10-volt battery and four 10-ohm resistors, as shown. Measure the current. A. Based on the voltage
iogann1982 [59]

Answer:

0.25 A

Resistance= 40 ohms

Explanation:

The first, and perhaps most important, the relationship between current, voltage, and resistance is called Ohm's Law, discovered by Georg Simon Ohm and published in his 1827 paper. Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. Introducing the constant of proportionality, the resistance, one arrives at the usual V=IR. Any Electrical device or component that obeys “Ohms Law” that is, the current flowing through it is proportional to the voltage across it ( I α V ), such as resistors or cables, are said to be “Ohmic” in nature.

Since we are not in a laboratory, we can not experimentally measure the current but it can be calculated from ohm's law.

Given that the four resistors are connected in series and

Req= R1 + R2 + R3 + R4

Since all are four ohm resistors

Req= 10 + 10+10+10 = 40ohms

Then;

V= 10 V

R= 40ohms

I= ???

From;

V=IR

I= 10/40

I= 0.25 A

6 0
3 years ago
Read 2 more answers
According to the Doppler effect what appears to happen when a light source moves further away from an observer
ludmilkaskok [199]

Answer: The correct answer is B. "the electromagnetic waves appear more red in color".

Explanation:

Scientists use the Doppler effect to understand the universe by determining the motion of the object.

Red shift: The apparent frequency of light decreases as the source object in space moves away from us.  The light is shifted to red end. The apparent frequency decreases and there is increase in the wavelength of the light.

Blue shift: The apparent frequency of light increases as the object in space moves towards us. The light is shifted to blue end. In this case, there is decrease in the wavelength of the light.  The frequency of the wave increases.

In the given problem, when the light source moves further away from an observer, the electromagnetic waves appear red in color.

Therefore, the correct option is (B).

6 0
3 years ago
Read 2 more answers
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