Answer:
0.686 g of ice melts each second.
Solution:
As per the question:
Cross-sectional Area of the Copper Rod, A = 
Length of the rod, L = 19.6 cm = 0.196 m
Thermal conductivity of Copper, K = 
Conduction of heat from the rod per second is given by:

where
= temperature difference between the two ends of the rod.
Thus

Now,
To calculate the mass, M of the ice melted per sec:

where
= Latent heat of fusion of water = 333 kJ/kg

<h2>Answer:</h2>
<u>A) Increase the voltage by adding a bigger battery </u>
<h2>Explanation:</h2>
According to Ohm's law
V = IR
where V is voltage, I is current and R is the resistance. If we write the equation for resistance we would get
R= V / I
Here we can see that Voltage is directly proportional to Resistance so in order to keep the balance if we increase the resistance then we must increase the voltage to keep the current constant.
Answer:
50 J
Explanation:
The net force acting on the box is given by the algebraic sum of the two forces, so:

The net work done on the box is equal to (assuming the net force is parallel to the displacement of the object)

where
F = 5 N is the net force on the object
d = 10 m is the displacement of the object
Substituting,

Answer:
this app is for solving doubts not sending links ok
I believe that this question has the following choices to
choose from:
placer deposits
fossil compaction
hydrothermal solutions
igneous processes
Actually among all, I have never encountered an ore that
formed due to fossil compaction. I suppose we can get minerals such as marble
or lime but not ores. So the answer is:
<span>fossil compaction (answer)</span>