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Feliz [49]
3 years ago
9

Describe the behavior of magnets

Physics
1 answer:
tatyana61 [14]3 years ago
8 0
They have a north and South Pole .The opposite poles attract to each other ,the same poles repel from each other.
You might be interested in
A scuba tank, when fully submerged, displaces 16.7 L of seawater. The tank itself has a mass of 13.4 kg and, when "full," contai
meriva

Answer:

m = 17.87 kg

Explanation:

As we know that tank itself has mass given as 13.4 kg

so it is given as

m_1 = 13.4 kg

also the tank contains air in it and the mass of air inside the tank is also given as 4.47 kg

so it is

m_2 = 4.47 kg

so total mass of the tank is the mass of the empty tank and mass of air in the tank

m = m_1 + m_2

m = 13.4 + 4.47

m = 17.87 kg

3 0
3 years ago
How to find the magnitude of a centripetal force?<br>(formula)​
frozen [14]

Answer:

F=mv^2÷r

Explanation:

i know every thing

the magnitude f of the centripetal force is equal to the mass m of the body times it veloctiy squared v^2 divided by the radius r of its path

4 0
3 years ago
A horizontal vinyl record of mass 0.10 kg and radius 0.10 m rotates freely about a vertical axis through its center with an angu
Tresset [83]

Answer:

The angular speed of the record is 3.36 rad/s.

Explanation:

Given that,

Mass of record= 0.10 kg

Radius = 0.10 m

Angular speed = 4.7 rad/s

Moment of inertia I=5.0\times10^{-4}\ kgm^2

Mass of putty = 0.020 kg

We need to calculate the angular speed

Using law of conservation of momentum

L_{i}=L_{f}

I\omega_{i}=(I+mr^2)\omega_{f}

\omega_{f}=\dfrac{I\omega_{i}}{(I+mr^2)}

Put the value into the formula

\omega_{f}=\dfrac{5.0\times10^{-4}\times4.7}{5.0\times10^{-4}+0.020\times(0.10)^2}

\omega_{f}=3.36\ rad/s

Hence, The angular speed of the record is 3.36 rad/s.

3 0
3 years ago
Explain how this increases their efficiency. Explain how this increases their efficiency. Antireflective coating causes the phas
sweet [91]

Answer:

c) True. If the coating cancels the light requested by the reflection, so there is more energy to enter the cell and therefore its efficiency increases

Explanation:

This exercise asks to analyze the effect of the antireflective coating on the efficiency of solar cells.

Let's start by expressing the expression for the interference of two light beams taken at when

* the phase change introduced when passing from air to 180º film

* the wavelength change by the refractive index of the film ln = lo / n

therefore the expression for destructive interference is

            2 n t = m λ

where m is an integer

with these concepts we can analyze the different statements

a) False. Phase shift does not change the wavelength of light

b) False. The refractive index of the solar cell is not affected by the refractive index of the film since the two materials do not mix.

c) True. If the coating cancels the light requested by the reflection, so there is more energy to enter the cell and therefore its efficiency increases

d) false. In solar cells the incidence is almost normal, therefore the effect of refraction (separation of colors for different angles) is very small

7 0
3 years ago
A satellite in a nearly circular orbit is 2000 km above earth's surface. the radius of earth is approximately 6400 km. if the sa
Ann [662]
Velocity is computed using the formula:

v= \frac{d}{t}
Where:
V = speed
d = distance traveled
t = time/period

First you need to consider that the orbit is circular. To get the measurement or the distance going around Earth, you will need to get the circumference of the path. 

C = 2 \pi r

Where:
C = circumference
π = 3.14
r = radius


The Earth has a radius of 6,400km, but you also need to consider that the satellite is orbiting above the surface of the Earth, so you add in the 2,000km to that radius. 

r = 6,400Km + 2,000Km = 8,400Km

Next step is to insert that into our circumference formula:

C = 2 \pi r
C = 2 \pi 8,400Km
C = 52,778.76 Km

The distance traveled would then be 52,778.76Km

Now that we have the distance, we can then get the velocity:

v= \frac{d}{t}
v= \frac{52,778.76Km}{12hrs}
v= 4,398.23km/hr

The speed of the satellite is 4,398.23km/hr.

7 0
3 years ago
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