You pull a 70-kg crate at an angle of 30° above the horizontal. If you pull with a force of 600N and the coefficient of kinetic
friction is .4, how far will it move in 3 seconds?
1 answer:
Answer:
Explanation:
Force of friction acting on the body = μ mg cosθ
= .4 x 70 x 9.8 x cos30
= 237.63 N
component of weight = mgsinθ
= 70 x 9.8 x sin30
= 343 N
Net upward force = 600 - mgsinθ - μ mg cosθ
= 600 - 343 - 237.63
= 105.37 N
acceleration in upward direction = 105.37 / 70
= 1.5 m /s²
s = ut + 1/2 a t²
= 0 + .5 x 1.5 x 3²
= 6.75 m .
You might be interested in
What is the value of the resistors? There are many types of resistors with different values for how much resistance they provide
Edit: My bad. Where are the resistors located
Hi how are you?
Are you a Libra?
Average Velocity=Total Distance/Total Time
Neither technician is correct.
Please don't touch my car.
Answer: D
Explanation: The chemical bonds in the food store energy that is released when we eat it.
