which tool would you use to measure the amount of rainfall? a. graduated cylinder b. stopwatch c. scale d. thermometer

An organ pipe is open at both ends. It is producing sound

ozzi

To solve this problem we will apply the concepts related to the wavelength of its third harmonic.

It describes that the wavelength is equivalent to

$\lambda = \frac{2}{3}L$

Here,

$\lambda = Wavelength$

The wavelength is in turn described as a function that depends on the change of the speed as a function of the frequency, that is to say

$\lambda = \frac{v}{f}$

In this case the speed is equivalent to the speed of sound and the frequency was previously given, therefore

$\lambda = \frac{343}{262}$

$\lambda = 1.3091m$

Finally the length of the pipe would be

$L= \frac{3}{2}(1.3091)$

$L = 1.963m$

3 0

3 years ago

To see if your results are reasonable, you can compare the final velocity of the stone as it falls down unwinding the wire from

pentagon [3]

Answer:

The velocity of the stone is 2.57 m/s.

Explanation:

Given that

Height = 0.337 m

We need to calculate the velocity of the stone

Using equation of motion

$v^2-u^2=2gh$

Where, v = velocity of stone

u = initial velocity

g = acceleration due to gravity

h = height

Put the value into the formula

$v^2-0=2\times9.8\times 0.337$

$v=\sqrt{2\times9.8\times0.337}$

$v=2.57\ m/s$

Hence, The velocity of the stone is 2.57 m/s.

7 0

4 years ago

We investigated a jet landing on an aircraft carrier. In a later maneuver, the jet comes in for a landing on solid ground with a

AlexFokin [52]

Answer:

Time is 14.8 s and cannot landing

Explanation:

This is a kinematic exercise with constant acceleration, we assume that the acceleration of the jet to take off and landing are the same

Calculate the time to stop, where it has zero speed

Vf² = Vo² + a t

t = - Vo² / a

t = - 110²/(-7.42)

t = 14.8 s

This is the time it takes to stop the jet

Let's analyze the case of the landing at the small airport, let's look for the distance traveled to land, where the speed is zero

Vf² = Vo² + 2 to X

X = -Vo² / 2 a

X = -110² / 2 (-7.42)

X = 815.4 m

Since this distance is greater than the length of the runway, the jet cannot stop

Let's calculate the speed you should have to stop on a track of this size

Vo² = 2 a X

Vo = √ (2 7.42 800)

Vo = 109 m / s

It is conclusion the jet must lose some speed to land on this track

4 0

3 years ago

A sound wave has frequency of 430 Hz in air . Which of these is closet to the wavelength of this sound? ( The speed of sound in

Darya [45]

I think it would be E. The higher the object the less wavelength is possible.

5 0

3 years ago

The velocity of blood flow is the lowest in capillaries because

Varvara68 [4.7K]

Answer:

the total cross-sectional area of the capillaries is greater than the total cross-sectional area of the arteries or any other part of the circulatory system.

Explanation:

Blood velocity is not the same in all areas. In the capillaries it is where there is less speed, while in arteries and veins it is quite similar. This is due to the cross-sectional area of each of the vessels. It is a mistake to think of a vein, artery or capillary individually. We have to put them all together to see that the total area of the capillaries is 100 times larger than that of the arteries or veins. Blood flowing through arteries or veins is going faster because there is less area.

Blood velocity is inversely proportional to each of the areas of its territories. The greater the area, the lower the speed.

6 0

3 years ago