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poizon [28]
2 years ago
9

A 2290 kg car traveling at 10.5 m/s collides with a 2780 kg car that is initially at rest at the stoplight. The cars stick toget

her and move 2.80 m before friction causes them to stop. Determine the coefficient of kinetic friction
Physics
1 answer:
avanturin [10]2 years ago
7 0

Answer:

0.41

Explanation:

given,

mass of the car, m = 2290 Kg

initial speed = 10.5 m/s

mass of another car, M = 2780 Kg

distance moved = 2.80 m

coefficient of friction = ?

conservation of energy

m u = (M + m) V

2290 x 10.5 = (2290 + 2780) V

V = 4.74 m/s

using equation of motion

v² = u² + 2 a s

4.74² = 2 x a x 2.8

a = 4.02 m/s²

now using equation

a = μ g

4.02 = μ x 9.8

μ = 0.41

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R1 + R4 = 1430 + 1350 = 2780 = R14    series combination of R1 & R4

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The circuit has been reduced to 3 resistors in parallel

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Explanation:

We can answer this question by using Newton's third law, which states that:

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Learn more about Newton's third law:

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