the correct answer is B. 1.27
Mechanical advantage of a lever is simply the ratio of the effort arm to the load arm.Effort arm is the distance from the pivot to the point of application of force while load arm is the distance of the lord from the pivot.
therefore, in this question, the effort arm is 0.28m while the load arm is 0.22 m. MA is calculated as follows: MA=effort arm/load arm
=0.28m/0.22m=1.27
Answer:
The same amount of energy is required to either stretch or compress the spring.
Explanation:
The amount of energy required to stretch or compress a spring is equal to the elastic potential energy stored by the spring:

where
k is the spring constant
is the stretch/compression of the spring
In the first case, the spring is stretched from x=0 to x=d, so

and the amount of energy required is

In the second case, the spring is compressed from x=0 to x=-d, so

and the amount of energy required is

so we see that the amount of energy required is the same.
Answer:
4.2 is the answer
Explanation
The image formed in a plane mirror is an equal distance behind the mirror as the object in front of it.
Step 1: the equation to this problem would be: 8.4/2
Step 2: 8.4 ÷ 2 = 4.2
0.03185A current is required in the windings for that to occur.
- Solenoids are essentially coils of cord. These generate a magnetic subject which strives a pressure over a steel element.A solenoid is a fundamental time period for a coil of cord that we use as an electromagnet.
- We additionally consult with the tool which could convert electric power into mechanical power as a solenoid.
- Actually it generates a magnetic subject for developing linear movement from the electrical cutting-edge. With using a magnetic subject.
- Magnetic field at the centre of a solenoid of length 'L' having 'N' number of turns with a current 'I' is given by
...(1)
It is given that 1000 turns uniformly distributed over a length of 0.400 m produces a magnetic field of magnitude 1.00 ×10⁻⁴T .
Putting above values in equation (1) , we get

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The work done by the applied force = 650 J
Given the mass of the box = 40 kg
The displacement of the box on applying force = 5 m
Applied horizontal force = 130 N
The co-efficient of friction between box and floor is = 0.3
We have to find the work done by the applied force.
Work done by the applied force = Applied Force x Displacement of the box
= 130 N x 5 m
= 650 J
[Here the unit Nm is known as Joule(J) ]
We have the co-efficient of friction. So,
The force applied due to friction = Mass of the box x Co-efficient of friction x Acceleration due to gravity
= 40 kg x 0.3 x 9.8
= 117.6 N
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