Answer:
Calculate the wavelength associated with an electron with energy 2000 eV.
Sol: E = 2000 eV = 2000 × 1.6 × 10–19 J
Answer:
12
N
in the direction opposite to electric field.
Explanation:
Force on a charged particle
q
due to electric field
E
is given by
→
F
=
q
→
E
|
F
|
=
−
0.06
C
×
200
N
C
=
−
12 N
Here negative indicates that force is in the direction opposite to electric field.
Answer:
600 m
Explanation:
Distance = speed × time
= (15)(40)
= <u>6</u><u>0</u><u>0</u><u> </u><u>m</u>
Answer:
The minimum thickness = 83.92 nm
Explanation:
The relation between the wavelength in a particular medium and refractive index 
where ;
= wavelength of the light in vacuum
n = refractive index of medium with respect to vacuum
For one phase change :
Replacing 1.43 for n and 480 nm for λ; we have:
t = 83.92 nm
Thus; the minimum thickness = 83.92 nm
Answer:
<h3>4.13m</h3>
Explanation:
Given
Horizontal velocity = 9.00m/s
time taken = 0.550 s
Required
How far does the projectile fall in the vertical direction
Using the formula for finding the maximum height of the projectile
H = U²sin²θ/2g where;
U = 9.00m/s
θ = 90° (object launched in the vertical direction)
g = 9.81m/s²
Substituting the given parameters into the formula;
H = 9²sin²90/2(9.81)
H = 81(1)/19.62
H = 81/19.62
H = 4.128 m
H ≈ 4.13m
Hence the distance that the projectile fall in the vertical direction is 4.13m
