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Gennadij [26K]
3 years ago
5

What is the magnitude of the velocity of a 25 kg mass that is moving with a momentum of 100 kg*m/s?

Physics
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer:

v= 4 m/s

Explanation:

Momenutm is, by definition, the product of mass and velocity.

p = mv

Let's replace what we know and solve for whatever's left

100 kg\cdot m/s = 25kg \cdot v \rightarrow v= 4 m/s

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After three shuttle accidents in three months, one of which resulted in a critical injury to a driver, Get Around Shuttle driver
alexandr1967 [171]

Answer:

Safety

Explanation:

As we know that safety is very important before doing anything .This is also a important part of the human needs.Every human wants both emotional and physical safety from his job or whatever is doing.

Maslow's given a Hierarchy of Needs and the second tier of this Hierarchy is safety.

So the answer of the given question is safety.

7 0
3 years ago
The net force experienced by an object is increased. What affect does this have on the acceleration of the object?
Evgesh-ka [11]

Answer:

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

Explanation:

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6 0
3 years ago
Analogy: atom is to element as ____ is to compound
Masja [62]
Molecule is the answer to what you are looking for

5 0
3 years ago
A speaker emits sound waves in all directions, and at a distance of 28 m from it the intensity level is 73 db. What is the total
Oduvanchick [21]

Answer:

P=0.197 Watt

Explanation:

Given That

B=73dB

Io= 1 * 10^-12

I=Io * 10^{\frac{B}{10} } \\I=2 * 10^{-5} Wm^{-2}  \\A=4 * pi * r^{2}\\ A=9852.03 m^{2}\\ Power= I * A\\P= 0.197 Watt

6 0
3 years ago
According to Kepler's Second Law the radius vector drawn from the Sun to a planet Multiple Choice is the same for all planets. s
Mademuasel [1]

Answer:

sweeps out equal areas in equal times.

Explanation:

As we know that there is no torque due to Sun on the planets revolving about the sun

so we will have

\tau_{net} = 0

now we have

\frac{dL}{dt}= 0

now we also know that

Area = \frac{1}{2}r^2d\theta

so rate of change in area is given as

\frac{dA}{dt} = \frac{1}{2}r^2\frac{d\theta}{dt}

so we will have

\frac{dA}{dt} = \frac{1}{2}r^2\omega

\frac{dA}{dt} = \frac{L}{2m}

since angular momentum and mass is constant here so

all planets sweeps out equal areas in equal times.

4 0
3 years ago
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