What would you use to to measure the weight of a truck?? I’m needing a word that is 8 letters long

Referring to the above diagram, how high will the ball rise on the right-hand incline?

Marina CMI [18]

I think it’s 15cm
Might be 7cm

3 0

3 years ago

If the distance to a distant galaxy is recorded as 10,000 light years, then light must have been traveling for 5000 years to rea

satela [25.4K]

False false false false

5 0

2 years ago

Read 2 more answers

Type of energy transformed into chemical energy by plants is called type of energy transformed into chemical energy by plants is

yuradex [85]

I think the correct answer is light energy. It is light energy that is transformed into chemical energy by plants by the process called photosynthesis. In this process, plants take in water, carbon dioxide, and sunlight and turn them into glucose and oxygen.

6 0

3 years ago

A small button placed on a horizontal rotating platform with diameter 0.320 m will revolve with the platform when it is brought

Otrada [13]

Answer:

0.2687 approximately 0.27

Explanation:

Diameter = 0.320

Speed = 40.0 rev/min

We are required to find coefficient of static friction between friction and button

The radius can be calculated as

0.320/2

= 0.160m

Then we have the rotational speed w = 40rev/min x 2pi/60

= 4.19 rad/s

umg = mrw²

u = mrw²/mg

u = rw²/g -------(1)

g = 9.8

When we put values into equation 1

0.150m x 4.19² / 9.8

= 0.150m x 17.5561 /9.8

= 0.2689

This is approximately 0.27

6 0

2 years ago

A long, hollow, cylindrical conductor (inner radius 3.4 mm, outer radius 7.3 mm) carries a current of 36 A distributed uniformly

Elden [556K]

Answer:

a. $B= 9.45 \times10^{-3} T$

b. $B= 0.820 T$

c. $B= 0.0584 T$

Explanation:

First, look at the picture to understand the problem before to solve it.

a. d1 = 1.1 mm

Here, the point is located inside the cilinder, just between the wire and the inner layer of the conductor. Therefore, we only consider the wire's current to calculate the magnetic field as follows:

To solve the equations we have to convert all units to those of the international system. (mm→m)

$B=\frac{u_{0}I_{w}}{2\pi d_{1}} =\frac{52 \times4\pi \times10^{-7} }{2\pi 1.1 \times 10^{-3}} =9.45 \times10^{-3} T\\$

μ0 is the constant of proportionality

μ0=4πX10^-7 N*s2/c^2

b. d2=3.6 mm

Here, the point is located in the surface of the cilinder. Therefore, we have to consider the current density of the conductor to calculate the magnetic field as follows:

J: current density

c: outer radius

b: inner radius

The cilinder's current is negative, as it goes on opposite direction than the wire's current.

$J= \frac {-I_{c}}{\pi(c^{2}-b^{2} ) }}$

$J=\frac{-36}{\pi(5.33\times10^{-5}-1.16\times10^{-5}) } =-274.80\times10^{3} A/m^{2}$

$B=\frac{u_{0}(I_{w}-JA_{s})}{2\pi d_{2} } \\A_{s}=\pi (d_{2}^{2}-b^2)=4.40\times10^{-6} m^2\\$

$B=\frac{6.68\times10^{-5}}{8.14\times10^{-5}} =0.820 T$

c. d3=7.4 mm

Here, the point is located out of the cilinder. Therefore, we have to consider both, the conductor's current and the wire's current as follows:

$B=\frac{u_{0}(I_w-I_c)}{2\pi d_3 } =\frac{2.011\times10^-5}{3.441\times10^{-4}} =0.0584 T$

As we see, the magnitud of the magnetic field is greater inside the conductor, because of the density of current and the material's nature.

3 0

3 years ago