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masha68 [24]
4 years ago
5

Convert the temperature 288 K to degrees Celsius

Physics
2 answers:
MArishka [77]4 years ago
6 0
Answer: 14.85°C

Justification:

1) To convert Kelvin temperature tu Celsius temperature you subtract 273.15

2) This is the formula.

°C = K - 273.15

3) The conversion of 288 K to degrees Celsius is:

°C = 288 - 273.15 = 14.85 K

Kelvin temperature is called absolute temperature. The lower bound of the absolute temperature is 0 K.<span>, that means absolute zero and it is physically impossible to reach.

At 0 K or absolute temperature the atoms would stop vibrating meining that the entropy of the substance reaches it's minimum value, i.e. 0

</span>Zero K is equivalent to - 273.15°C
Bumek [7]4 years ago
6 0

i dont know how to convert it but you can use goolge to transfer it

288 kelvin = 14.85 celsius

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Explanation:

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We are running late for school and we want to make our 0.5 kg tea (it’s at 90 C) colder. Let’s assume we can drink tea when it’s
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1) How is the temperature of a gas related to the kinetic energy of its particles?
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What is the average velocity of atoms in 2.00 mol of neon (a monatomic gas)
Dimas [21]

Answer:

v = 876 m/s

Explanation:

It is given that,

Number of mol of Neon is 2 mol

Temperature, T = 308 K

Mass, m = 0.02 kg

Value of R - 8.31 J/mol-K

We need to find the average velocity of atoms in 2.00 mol of neon. Neon is a monoatomic gas. Let v is the velocity. So,

\dfrac{1}{2}mv^2=\dfrac{3}{2}nRT\\\\v=\sqrt{\dfrac{3nRT}{m}} \\\\v=\sqrt{\dfrac{3\times 2\times 8.314\times 308}{0.02}} \\\\v=876.47\ m/s

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8 0
3 years ago
Read 2 more answers
Peter’s body supplies a force of 500 N to run up a 10-m hill in 10 s. How much power is involved in Peter’s run up the hill? Exp
shutvik [7]

Answer: 500 Watts

Explanation:

Power P is the speed with which work W is done. Its unit is Watts (W), being 1 W=\frac{1 Joule}{1 s}.

Power is mathematically expressed as:

P=\frac{W}{t} (1)

Where t is the time during which work W  is performed.

On the other hand, the Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  It is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter (1J=(1N)(1m)=Nm  ).

When the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:  

W=(F)(d) (2)

In this case, we have the following data:

F=500 N

d=10 m

t=10 s

So, let's calculate the work done by Peter and then find how much power is involved:

From (2):

W=(500 N)(10 m) (3)

W=5000 J (4)

Substituting (4) in (1):

P=\frac{5000 J}{10 s} (5)

Finally:

P=500 W

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