Noise from highways are a significant issue. particularly for those who live close to the highway
Answer:
<em>I think the answer is C</em>
<em />
Explanation:
Its heavy but not too heavy
Wow! 2.95m/s is a mighty fast pace for a backpacker. Must have one of those Star Wars anti-gravity packs. Also, I would be curious as to why she passed her destination and then walked back.
<span>Anyway, it goes like this: </span>
<span>Say the time walking east is 't', and the total time is 'T'. </span>
<span>Then 5340 m + .511 t = 1.43 T </span>
<span>(This assumes that velocity is positive in both directions) </span>
<span>Two unknowns in one equation. But you also know that the time spent walking west is </span>
<span>5340m/ 2.95m/s = 1810 sec. </span>
<span>and the total time T = 1810 +t </span>
<span>Substitute this into the first equation, and you can solve for t = 3092 sec. </span>
<span>Then T = 4902 sec. and distance walked east is .511t = 1580m.</span>
This Question is not complete
Complete Question:
a. A hawk flies in a horizontal arc of radius 11.3 m at a constant speed of 5.7 m/s. Find its centripetal acceleration.
Answer in units of m/s2
b. It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s2. Find the magnitude of acceleration under
these new conditions.
Answer in units of m/s2
Answer:
a. 2.875m/s²
b. 3.172m/s²
Explanation:
a. The formula for centripetal acceleration = (speed²) ÷ radius
Centripetal acceleration = (5.7m/s)²÷ 11.3m
Centripetal acceleration = 2.875m/s²
b. Magnitude of acceleration can be calculated by finding the sum of the vectors for the both the centripetal acceleration and the increase in the speed rate.
Centripetal acceleration ( acceleration x) = 2.875m/s²
Increase in the speed rate ( acceleration n) = 1.34m/s²
Magnitude of acceleration = √a²ₓ + a²ₙ
=√( 2.875m/s²)²+ (1.34m/s²)²
= √ 10.06m/s²
= 3.172m/s²
Answer:
F = 17.3 kN
Explanation:
The normal force must support the weight of the car plus provide for the needed centripetal acceleration.
F = m(g + v²/R ) = 1000(9.8 + 15²/30) = 17,300
