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777dan777 [17]
3 years ago
8

The thermite reaction, in which powdered aluminum reacts with iron oxide, is highly exothermic: 2Al(s) + F e2O3 (s)→A l2O 3 (s) 

+ 2Fe(s) Use standard enthalpies of formation to find ΔH ∘ rxn for the thermite reaction.
Chemistry
1 answer:
bija089 [108]3 years ago
4 0
For this problem, we use the Hess' Law.

ΔHrxn = ∑(ν*Hf of products) - ∑(ν*Hf of reactants)

The ν represents the corresponding stoichiometric coefficients of the substances, while Hf is the heat of formation. For pure elements, Hf = 0.

Hf of Al₂O₃ = <span>−1676.4 kJ/mol
</span>Hf of Fe₂O₃ = <span>-826.0 kJ/mol

Thus,

</span>ΔHrxn = 1*−1676.4 kJ/mol + 1*-826.0 kJ/mol
<em>ΔHrxn = -2502.4 kJ/mol</em>
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What is the number of moles of kf in a 29-gram sample of the compound.
Irina18 [472]

<em><u>Given</u></em>

Weight of pottasium fluoride (KF) = 29 gms

<em><u>To find</u></em>

Number of moles of pottasium fluoride = ?

<em><u>Solution</u></em>

we know that molar mass of KF = 58.0967 g

Now,

number \:  of  \: moles = \ \\ \frac{given \: weight \: of \: subtance}{molar \: mass}

<em>Number of moles = 29/58 = 0.5 moles</em>

<u><em>Thanks</em><em> </em><em>for</em><em> </em><em>joining</em><em> </em><em>brainly</em><em> </em><em>community</em></u>

6 0
2 years ago
Fruit salad is an example of what? compound homogeneous mixture element heterogeneous mixture
salantis [7]
The answer is homogeneous mixture
3 0
4 years ago
A Cu2+ solution is prepared by dissolving a 0.4749 g piece of copper wire in acid. The solution is then passed through a Walden
Luda [366]

Answer:

Concentration of Cr_2O_7^{2-} = 0.03101 M

Concentration of MnO_4^- = 0.03721 M

Explanation:

A)

The reduction for Cr_2O_7^{2-} is;

Cr_2O_7^{2-} + 14 H ^+ _{(aq)}  + 6 e^- -----> 2 Cr^{3+} _{(aq)}+7H_2O _{(l)}

Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-

6 moles of Cu ^+ = 1 mole of Cr_2O_7^{2-}

number of moles of Cu reacted = \frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }

number of moles of Cu reacted = \frac{0.4749}{63.55}

number of moles of Cu reacted = 0.00747 mole

number of moles of Cr_2O_7^{2-}reacted = \frac{0.00747}{6}

number of moles of Cr_2O_7^{2-}reacted = 0.001245 mole

Concentration of Cr_2O_7^{2-} = \frac{number \ of moles }{Volume}

Given that the volume = 40.15 mL = 40.15 *10^{-3}; we have:

Concentration of Cr_2O_7^{2-} = \frac{0.001245}{40.15*10^{-3}}

Concentration of Cr_2O_7^{2-} = 0.03101 M

B)

The reduction for MnO_4^- is;

MnO_4^- + 8H^+ + 5 e^- -----> Mn^{2+} + 4H_2O

Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-

5 moles of Cu ^+ = 1 mole of Cr_2O_7^{2-}

number of moles of Cu reacted = \frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }

number of moles of Cu reacted = \frac{0.4749}{63.55}

number of moles of Cu reacted = 0.00747 mole

number of moles of MnO_4^- reacted = \frac{0.00747}{5}

number of moles of MnO_4^- reacted = 0.001494 mole

Concentration of MnO_4^- = \frac{number \ of moles }{Volume}

Given that the volume = 40.15 mL = 40.15 *10^{-3}; we have:

Concentration of MnO_4^- = \frac{0.001494 }{40.15*10^{-3}}

Concentration of MnO_4^- = 0.03721 M

3 0
4 years ago
A sample of gas kept at a constant pressure, is heated from 273 k to 373 k. If the initial volume is 3.00 L, what is the new vol
zlopas [31]

Answer: 4.10 liters

Explanation:

Given that:

initial volume of gas V1 = 3.0L

initial temperature of gas T1 = 273K

new volume V2 = ?

new temperature T2 = 373K

Since, only volume and temperature are involved, apply the formula for Charle's law

V1/T1 = V2/T2

3.0L/273K = V2/373K

To get the value of Z, cross multiply

3.0L x 373K = 273K x V2

1119 = 273V2

Divide both sides by 273

1119/273 = 273V2/273

4.10L = V2

Thus, the new volume is 4.10 liters

6 0
3 years ago
How many mole of fe203 are in 233g og the compound
Vadim26 [7]
The answer to this question
Is : 193g
3 0
3 years ago
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