Answer:
The answer to your question is 3 ml
Explanation:
Data
Dosage = 9.0 mg/ kg
Child's weight = 42.9 pounds
Suspension = 60 mg/ml
milliliters = ?
Process
1.- Convert the weight to kg
1 pound ------------------- 0.453 kg
42.9 pounds --------------- x
x = (42.9 x 0.453) / 1
x = 19.43 kg
2.- Calculate the milligrams the child needs
1 kg of weight ------------ 9 mg
19.43 kg ---------------------- x
x = (19.43 x 9) / 1
x = 174.87 mg of oxcarbazepine
3.- Calculate the milliliters needed
60 mg of suspension ------------- 1 milliliters
174.87 mg -------------- x
x = (174.87 x 1) / 60
x = 2.9 ml ≈ 3 ml
The given question is incorrect. The correct question is as follows.
If 20.0 g of
and 4.4 g of
are placed in a 5.00 L container at
, what is the pressure of this mixture of gases?
Explanation:
As we know that number of moles equal to the mass of substance divided by its molar mass.
Mathematically, No. of moles = 
Hence, we will calculate the moles of oxygen as follows.
No. of moles = 
Moles of
=
= 0.625 moles
Now, moles of 
= 0.1 moles
Therefore, total number of moles present are as follows.
Total moles = moles of
+ moles of 
= 0.625 + 0.1
= 0.725 moles
And, total temperature will be:
T = (21 + 273) K = 294 K
According to ideal gas equation,
PV = nRT
Now, putting the given values into the above formula as follows.
P =
= 
=
atm
= 3.498 atm
or, = 3.50 atm (approx)
Therefore, we can conclude that the pressure of this mixture of gases is 3.50 atm.
Answer:
Groundwater pollution
Explanation:
Pesticides, when sprayed on crop plants, are able to flow below the surface of the ground, reaching water-bearing aquifers, thereby contaminating groundwater, making it unsuitable for both human and agricultural uses.