A would be the correct answer. Its the only one to make sense since you are trying to solve the conflict!
Yes if you need to know why i will tell you why
Answer:
D) negative, due to extra electrons.
Explanation:
The charge that would be gained will be negative charges due to extra electrons.
Electrons are usually lost or gained by bodies that comes in contact with one another.
They occupy the orbital space in an atom and are not strongly held by forces within the atom.
Protons cannot be lost in such manner. They occupy the nucleus and are bounded by strong chemical forces within it.
The polythene and rods are both made up of chemical substances whose units called atoms are made up of subatomic particles of protons, neutrons and electrons. As with all kinds of matter, there would be pool of free electrons round them that can easily be rubbed off due to the weak attractive forces binding them in the atomic sphere.
When the polythene and rods are rubbed, there would be a loss of electrons and the gaining body, polythene becomes negatively charged.
Answer:
0.0118125 (kg)
Explanation:
mass = density x volume
First, find the volume of the cube as you're already given the density. You're also given the length of the cube, 1.5 cm. You need to convert this to m since the density's unit is kg/m^2
1.5cm x (1m/100cm) = 0.015m
Since Volume = (length)^3,
Volume of the cube = (0.015)^3
Volume of the cube = 3.375*10^-6
So mass of the cube = (3500)(3.375*10^-6) = 0.0118125 (kg)
Explanation:
Ohm's law describes the relationship between voltage, current, and resistance.
V = IR
where V is voltage, I is current, and R is resistance.
A. At the original voltage:
V₁ = I₁ R₁
When the voltage is doubled and resistance stays the same:
2V₁ = I₁' R₁
Dividing the two equations:
2V₁ / V₁ = (I₁' / I₁) (R₁ / R₁)
2 = I₁' / I₁
So the new current is double the original current.
B. At the original voltage and resistance:
V₂ = I₂ R₂
When both the voltage and resistance are increased by a factor of 2:
2V₂ = I₂' (2R₂)
Dividing the two equations:
(2V₂ / V₂) = (I₂' / I₂) (2R₂ / R₂)
2 = (I₂' / I₂) (2)
1 = I₂' / I₂
So the new current is the same as the original current.
