All categories

3 years ago

What acceleration is imparted to a football when the player kicked it with a force of 25 N? mass of football=0.40 kg

1 answer:

6 0

Force = mass x acceleration

25N = 0.40kg x acceleration
25N/0.40kg = acceleration

acceleration = 62.5 N/kg
N/kg is the equivalent of m/s²

So your acceleration is 62.5 meters per second squared

You might be interested in

Look at the circuit diagram. Which of these components is part of the circuit?

Roman55 [17]

Answer:

b ac power source

Explanation:

ieififuffucjcjcicogore8e8e9e9e9e9ew0ww0w0w

7 0

2 years ago

Individuals who suffer from a mental disorder are most likely to commit violent crimes. true or false

Damm [24]

That is true. Some people with mental disorders envision the world differently. Some people think that people are out to get them, they are in another world, etc. They will do anything to feel safe in their mental state.

I hope this helps!
~cupcake

7 0

3 years ago

Read 2 more answers

A 100 kg cart goes around the inside of a vertical loop of a roller coaster. The radius of the loop is 3 m and the cart moves at

Sphinxa [80]

Answer:

200 N

Explanation:

8 0

3 years ago

According to the equation for the Balmer line spectrum of hydrogen, a value of n = 3 gives a red spectral line at 656.3 nm, a va

nirvana33 [79]

Answer:

E3 = 3.03 10⁻¹⁶ kJ, E4 = 4.09 10⁻¹⁶ kJ and E5 = 4.58 10⁻¹⁶ kJ

Explanation:

They give us some spectral lines of the Balmer series, let's take the opportunity to place the values in SI units

n = 3 λ = 656.3 nm = 656.3 10⁻⁹ m

n = 4 λ = 486.1 nm = 486.1 10⁻⁹ m

n = 5 λ=434.0 nm = 434.0 10⁻⁹ m

Let's use the Planck equation

E = h f

The speed of light equation

c = λ f

replace

E = h c /λ

Where h is the Planck constant that is worth 6.63 10⁻³⁴ J s and c is the speed of light that is worth 3 10⁸ m / s

Let's calculate the energies

E = 6.63 10⁻³⁴ 3 10⁸ / λ

E = 19.89 10⁻²⁶ /λ

n = 3

E3 = 19.89 10⁻²⁶ / 656.3 10⁻⁹

E3 = 3.03 10⁻¹⁹ J

1 kJ = 10³ J

E3 = 3.03 10⁻¹⁶ kJ

n = 4

E4 = 19.89 10⁻²⁶ /486.1 10⁻⁹

E4 = 4.09 10⁻¹⁹ J

E4 = 4.09 10⁻¹⁶ kJ

n = 5

E5 = 19.89 10⁻²⁶ /434.0 10⁻⁹

E5 = 4.58 10⁻¹⁹ J

E5 = 4.58 10⁻¹⁶ kJ

7 0

3 years ago

Two carts, one of mass 2m and one of mass m, approach each other with the same speed, v. When the carts collide, they hook toget

Nikitich [7]

Answer:

<em>Second option</em>

Explanation:

<u>Linear Momentum</u>

The linear momentum of an object of mass m and speed v is

P=mv

If two or more objects are interacting in the same axis, the total momentum is

$P_t=m_1v_1+m_2v_2+...$

Where the speeds must be signed according to a fixed reference

The images show a cart of mass 2m moves to the left with speed v since our reference is positive to the right

$P_1=-2mv$

The second cart of mass m goes to the right at a speed v

$P_2=mv$

The total momentum before the impact is

$P_t=-2mv+mv=-mv$

The total momentum after the collision is negative, both carts will join and go to the left side

The first option shows both carts with the same momentum before the collision and therefore, zero momentum after. It's not correct as we have already proven

The third option shows the 2m cart has a positive greater momentum than the other one. We have proven the 2m car has negative momentum. This option is not correct either

The fourth option shows the two carts keep separated after the collision, which contradicts the condition of the question regarding "they hook together".

The second option is the correct one because the mass $m_2$ has a negative momentum and then the sum of both masses keeps being negative

3 0

3 years ago

Read 2 more answers