I just took it 100% 11/11
1.D
2.A
3.A
4.A
5.B
6.C
7.D
8C
9A
10B
11C
Answer:
Explanation:
Given that,
Mass of block
M = 2kg
Spring constant k = 300N/m
Velocity v = 12m/s
At t = 0, the spring is neither stretched nor compressed. Then, it amplitude is zero at t=0
xo = 0
It velocity is 12m/s at t=0
Then, it initial velocity is
Vo = 12m/s
Then, amplitude is given as
A = √[xo + (Vo²/ω²)]
Where
xo is the initial amplitude =0
Vo is the initial velocity =12m/s
ω is the angular frequency and it can be determine using
ω = √(k/m)
Where
k is spring constant = 300N/m
m is the mass of object = 2kg
Then,
ω = √300/2 = √150
ω = 12.25 rad/s²
Then,
A = √[xo + (Vo²/ω²)]
A = √[0 + (12²/12.5²)]
A = √[0 + 0.96]
A = √0.96
A = 0.98m
Answer
b. the number of atoms in each molecule.
Explanation:
The power equals energy divided by the time
P=E/t
P=1200/60
P=20W
Hope you get it!
Answer:
change in relative vorticity 0.0590
Explanation:
Given data
pressure = 1000 hPa
temperature lapse rate q1 = 3.1◦C per 50 hPa
pressure = 850 hPa
temperature lapse rate q2= -0.61◦C per 50 hPa
to find out
change in relative vorticity
solution
we will apply here formula that is
N = (g / potential temperature ) × (potential vertical temperature) × exp^1/2 ............................1
here we know g = 9.8 m/s
and q1 = potential temperature=3.3 degree celsius
potential vertical temperature gradient = 3.1 - 0.61 / 1000 -850
potential vertical temperature gradient = 0.0166 degree celsius/hpa
so
N = 9.8 / 2.75 × 0.0166 × exp^1/2
N = 0.0590
