How could you weaken the force of gravity between cars and the Earth?**I WILL MARK BRAINLEST**
1 answer:
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Answer:
866.32 N
Explanation:
The diagram explains better.
Taking the total moment of forces, the sum of the clockwise moment of forces about the fulcrum must be equal to the sum of the anticlockwise moment of forces about the fulcrum:
F * (1.9 - 0.65) = 170 * 9.8 * 0.65
F * 1.25 = 1082.9
F = 1082.9/1.25
F = 866.32 N
A force of 866.32 N is needed to move the rock.
Answer:
24 m
Explanation:
The motion of the car is a uniformly accelerated motion (=at constant acceleration), therefore we can find the distance covered by using the following suvat equation:
where
s is the distance covered
u is the initial velocity
t is the time elapsed
a is the acceleration
For the car in this problem:
u = 0, since the car starts from rest
is the acceleration
t = 4 s is the time elapsed
Therefore, the distance covered is:
Answer:
q = 224 mm, h ’= - 98 mm, real imagen
Explanation:
For this exercise let's use the constructor equation
where f is the focal length, p and q are the distance to the object and the image respectively.
In a mirror the focal length is
f = R / 2
indicate us radius of curvature is equal to the diameter of the eye
R = 3,50 10² mm
f = 3.50 10² /2 = 1.75 10² mm
they also say that the distance to the object is p = 0.800 10³ mm
1 / q = 1 / f - 1 / p
1 / q = 1 / 175 - 1 /800
1 / q = 0.004464
q = 224 mm
to calculate the size let's use the magnification ratio
m =
h '=
h ’= - 224 350 / 800
h ’= - 98 mm
in concave mirrors the image is real.