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3 years ago

Explain why organisms are more likely to be well preserved in mud than in sand

Chemistry

1 answer:

Vsevolod [243]3 years ago

3 0

Mud has alot of water so it's easier for them to live in.

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(C6H6) can be biodegraded by microorganism. if 30 mg of benzene is present, what amount of oxygen required for biodegradation, n

quester [9]

Answer:

36.92 mg of oxygen required for bio-degradation.

Explanation:

$5C_6H_6+15O_2\rightarrow 12CO_2+15H_2O$

Mass of benzene = 30 mg = 0.03 g (1000 mg = 1 g )

Moles benzene = $\frac{0.03 g}{78 g/mol}=0.0003846 mol$

According to reaction 5 moles of benzene reacts with 15 moles of oxygen gas.

Then 0.0003846 mol of benzene will react with:

$\frac{15}{5}\times 0.0003846 mol=0.0011538 mol$ of oxygen gas

Mass of 0.0011538 moles of oxygen gas:

0.0011538 mol × 32 g/mol = 0.03692 g = 36.92 mg

36.92 mg of oxygen required for bio-degradation.

4 0

3 years ago

Why is pyridine included in the reaction of an acid chloride and an amine or alcohol? Pyridine will deprotonate the amine or alc

Pavel [41]

Answer:

Pyridine will neutralize the acid by-product of the reaction.

Explanation:

In the esterifications, hydrochloric acid is released as a by-product that reacts directly with the pyridine in the medium to give the pyridine hydrochloride.

7 0

3 years ago

Sum of all forces acting on object is it a forces, unbalanced forces , balanced forces, net forces

malfutka [58]

Answer: The answer is Net Forces.

Net force is the vector sum of forces acting on a particle or body.

Have a great day!

8 0

3 years ago

Read 2 more answers

What mass of silver chloride can be produced from 1.73 l of a 0.147 m solution of silver nitrate?

dsp73

36.49 gm using law of equivalent proportion

4 0

3 years ago

According to the following reaction, how many grams of potassium sulfate will be formed upon the complete reaction of 23.8 grams

Alexxandr [17]

Answer: The mass of potassium sulfate that can be produced is 73.88 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For KOH:

Given mass of KOH = 23.8 g

Molar mass of KOH = 56.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of KOH}=\frac{23.8g}{56.1g/mol}=0.424mol$

The chemical equation for the reaction of KOH and potassium hydrogen sulfate follows:

$KHSO_4+KOH\rightarrow K_2SO_4+H_2O$

As, potassium hydrogen sulfate is present in excess. It is considered as an excess reagent.

KOH is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of KOH produces 1 mole of potassium sulfate

So, 0.424 moles of KOH will produce = $\frac{1}{1}\times 0.424=0.424moles$ of potassium sulfate

Now, calculating the mass of potassium sulfate from equation 1, we get:

Molar mass of potassium sulfate = 174.26 g/mol

Moles of potassium sulfate = 0.424 moles

Putting values in equation 1, we get:

$0.424mol=\frac{\text{Mass of potassium sulfate}}{174.26g/mol}\\\\\text{Mass of potassium sulfate}=(0.424mol\times 174.26g/mol)=73.88g$

Hence, the mass of potassium sulfate that can be produced is 73.88 grams

8 0

3 years ago