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bija089 [108]
3 years ago
6

Is anyone good at chemistry if so Can someone help me please NO LINKS

Chemistry
1 answer:
Nookie1986 [14]3 years ago
4 0

Answer:

6.25 g

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 68.8 years

Time (t) = 344 years

Original amount (N₀) = 200 g

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Half-life (t½) = 68.8 years

Time (t) = 344 years

Number of half-lives (n) =

n = t / t½

n = 344 / 68.8

n = 5

Thus, 5 half-lives has elapsed.

Finally, we shall determine the amount of the Uranium-232 that remains. This can be obtained as follow:

Original amount (N₀) = 200 g

Number of half-lives (n) = 5

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2⁵ × 200

N = 1/32 × 200

N = 200 / 32

N = 6.25 g

Thus, the amount of Uranium-232 that remains is 6.25 g

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b. Analysis. In the analysis step, you organize and interpret your data to see if they support your hypothesis.

a. Experimentation is <em>incorrect</em> because this is the step in which you do experiments to test if your prediction is accurate.

c. Conclusion is <em>incorrect</em> because a conclusion is a decision you make to accept or reject your hypothesis.

d. Hypothesis is <em>incorrect</em> because a hypothesis is a proposed explanation for why something happens.

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3 years ago
Need help with this question.... Next to each Formula, write the number of atoms of each element found in one unit of the compou
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Answer:

The number of atoms present in one unit of the following compounds is:

a). Potassium Iodide , KI = 2

b).Sodium Sulfide, Na_{2}S = 3

c). Silicon Dioxide , SiO_{2} = 3

d). Carbonic Acid ,H_{2}CO_{3} = 6

Explanation:

Atomicity : It is defined as the number of atoms that are present in a given molecule/compound.

Atom : The smallest unit of matter is called atom. For e.g O is atom of oxygen but O_{2} is not an atom , it is molecule of oxygen .

O_{2} molecule has 2 atoms of Oxygen

Similarly  Na , K , Fe are atoms but O_{2} ,CO_{2} ,N_{2},H_{2}  are molecules

a).Potassium Iodide

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b) Sodium Sulfide

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Total atoms = 3

c) Silicon Dioxide

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Total atoms = 3

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7 0
3 years ago
mixture of N 2 And H2 Gases weighs 13.22 g and occupies a volume of 24.62 L at 300 K and 1.00 atm.Calculate the mass percent of
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<u>Answer:</u> The mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of the gaseous mixture = 1.00 atm

V = Volume of the gaseous mixture = 24.62 L

n = number of moles of the gaseous mixture = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gaseous mixture = 300 K

Putting values in above equation, we get:

1.00atm\times 24.62L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\n_{mix}=\frac{1.00\times 24.62}{0.0821\times 300}=0.9996mol

We are given:

Total mass of the mixture = 13.22 grams

Let the mass of nitrogen gas be 'x' grams and that of hydrogen gas be '(13.22 - x)' grams

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

<u>For nitrogen gas:</u>

Molar mass of nitrogen gas = 28 g/mol

\text{Moles of nitrogen gas}=\frac{x}{28}mol

<u>For hydrogen gas:</u>

Molar mass of hydrogen gas = 2 g/mol

\text{Moles of hydrogen gas}=\frac{(13.22-x)}{2}mol

Equating the moles of the individual gases to the moles of mixture:

0.9996=\frac{x}{28}+\frac{(13.22-x)}{2}\\\\x=12.084g

To calculate the mass percentage of substance in mixture we use the equation:

\text{Mass percent of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100

Mass of the mixture = 13.22 g

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Mass of nitrogen gas = x = 12.084 g

Putting values in above equation, we get:

\text{Mass percent of nitrogen gas}=\frac{12.084g}{13.22g}\times 100=91.41\%

  • <u>For hydrogen gas:</u>

Mass of hydrogen gas = (13.22 - x) = (13.22 - 12.084) g = 1.136 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen gas}=\frac{1.136g}{13.22g}\times 100=8.59\%

Hence, the mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

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Answer:

D. two-stroke cylinder engine.

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