Well I wouldn't quite call it a third eye but yes we have the ability to see things if we connect to our inner selves
Hypoventilation can cause oxygen levels to fall too low, a condition called Hypoxia and carbon dioxide levels may rise too high, a condition called Hypercapnia.
Hypoxia is a state in which there is insufficient oxygen reaching the tissues of the body or a specific area of the body.
Generalized hypoxia, which affects the entire body, and local hypoxia, which affects a specific area of the body, are the two types of hypoxia.
Although fluctuations in arterial oxygen concentrations are frequently associated with clinical conditions, they can also occur naturally during severe physical activity or hypoventilation training.
A rise in carbon dioxide partial pressure (PaCO2) above 45 mmHg is referred to as hypercapnia.
The body produces carbon dioxide as a metabolic byproduct of its numerous cellular functions, and it has a number of physiological systems at its disposal to control its levels.
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Answer:
C8H17N
Explanation:
Mass of the unknown compound = 5.024 mg
Mass of CO2 = 13.90 mg
Mass of H2O = 6.048 mg
Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:
For carbon, C:
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Mass of C = 12/44 x 13.90 = 3.791 mg
For hydrogen, H:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H = 2/18 x 6.048 = 0.672 mg
For nitrogen, N:
Mass N = mass of unknown – (mass of C + mass of H)
Mass of N = 5.024 – (3.791 + 0.672)
Mass of N = 0.561 mg
Now, we can obtain the empirical formula for the compound as follow:
C = 3.791 mg
H = 0.672 mg
N = 0.561 mg
Divide each by their molar mass
C = 3.791 / 12 = 0.316
H = 0.672 / 1 = 0.672
N = 0.561 / 14 = 0.040
Divide by the smallest
C = 0.316 / 0.04 = 8
H = 0.672 / 0.04 = 17
N = 0.040 / 0.04 = 1
Therefore, the empirical formula for the compound is C8H17N
To determine the formula units of the given compound, we need to convert from grams to moles first then convert it to formula units by using the Avogadro's number. We do as follows:
23.5 g <span>Sb2S3 ( 1 mol / 339.7 g ) ( 6.022 x 10^23 formula units / mol ) = 4.17x10^22 formula units </span><span>Sb2S3</span>
