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Serga [27]
3 years ago
11

The acceleration due to gravity on the surface of Mars is about one third the acceleration due to gravity on Earth’s surface. Th

e weight of a space probe on the surface of Mars is about _____.
Physics
2 answers:
Marat540 [252]3 years ago
6 0

Answer:

\frac{2}{5}

Explanation:

Thinking process:

The weight of an object if defined as the gravitational pool on the object. This is the force that pulls an object downward. This is given as follows:

W = mg

where w = weight (gravitational pull)

           m = mass of the object (kg)

           g  = acceleration due to gravity (m/s²)

The acceleration due to gravity on Mars is about 3.924 m/s². This is \frac{2}{5} of the acceleration on the earth.

Therefore, the weight of the object on Mars will weigh 2/5 of what it weighs on earth.

Lorico [155]3 years ago
3 0
1/3 the weight than it is on earth, duh
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Answer:

Engular velocity: w=1,24*10^{-3}/s

Linear velocity: V=7905 m/s

The time it takes:

t=5060s=84min

Explanation:

The magnitude of the centripetal acceleration can be related to the angular velocity and radius as:

(1)a=r*w^{2}

Solving for w:

(2)w=\sqrt{\frac{a}{r} }

Replacing a=9,8m/s2 and r=6,375,000m:

(3)w=\sqrt{\frac{9,8m/s^{2}}{6375000m} }=1,24*10^{-3}/s

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V=w*r=1,24*10^{-3}/s*6375000m=7905 m/s

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P=\pi *2*r=\pi *2*6375000m=40.05*10^{6}m

The time it takes:

t=\frac{P}{V} =\frac{40.05*10^{6}m}{7905 m/s}=5060s=84min

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