Ask question

Ask question

All categories

3 years ago

12

If you are in a rear-wheel skid, you must release your brakes and turn your steering wheel __________

1 answer:

g100num [7]3 years ago

3 0

I think the correct answer would be A. If you are in a rear-wheel skid, you must release your brakes and turn your steering wheel into the direction of the skid. A skid in vehicles is a situation wherein one or more wheels are slipping in relation to the road and affecting the whole handling of the vehicle. To do a rear wheel skid, you should be releasing the break with caution and move or steer the wheel into the direction you would want to move.

You might be interested in

A 2.5 g bullet traveling at 350 m/s hits a tree and slows uniformly to a stop while penetrating a distance of 12 cm into the tre

Cloud [144]

Answer: Work done = 153.125Joules, Work done = 0.003Nm

Explanation:

Kinetic energy of a body is the energy possessed by a body by virtue of its motion.

Mathematically,

K.E = 1/2MV²

Where;

M = mass of the body = 2.5g = 0.0025kg

V = velocity of the body = 350m/s

Substituting this values in the formula, we have;

K.E = 1/2× 0.0025×350²

K.E = 153.125Joules

Work done is the force applied to body to cause it to move through a distance.

Work = Force × distance

Force = ma = 0.0025 × 10

Force = 0.025N

Distance = 12cm = 0.12m

Work = 0.025×0.12

Work = 0.003Nm

work done by the tree in stopping the bullet is 0.003N

4 0

3 years ago

Read 2 more answers

point) A circular swimming pool has a diameter of 12 m. The circular side of the pool is 3 m high, and the depth of the water is

Sergio [31]

Answer:

(a) 86.65 J

(b) 149.65 J

Solution:

As per the question:

Diameter of the pool, d = 12 m

⇒ Radius of the pool, r = 6 m

Height of the pool, H = 3 m

Depth of the pool, D = 2.5 m

Density of water, $\rho_{w} = 1000\ kg//m^{3}$

Acceleration due to gravity, g = $9.8\ m/s^{2}$

Now,

(a) Work done in pumping all the water:

Average height of the pool, h = $\frac{H + D}{2}$

h = $\frac{3 + 2.5}{2} = 2.75\ m$

Volume of water in the pool, V = $\pi r^{2}h = \pi \times 6^{2}\times 2.75 = 311.02\ m^{3}$

Mass of water, $m_{w} = \frac{\rho_{w}}{V}$

$m_{w} = \frac{1000}{311.02} = 3.215\ kg$

Work done is given by the potential energy of the water as:

$W = m_{w}gh = 3.215\times 9.8\times 2.75 = 86.65\ J$

(b) Work done to pump all the water through an outlet of 2 m:

Now,

Height, h = 2.75 + 2 = 4.75

Work done, $W = m_{w}gh = 3.215\times 9.8\times 4.75 = 149.65\ J$

7 0

3 years ago

What force in Newton is required to accelerate a car starting from rest to 20 m/s in 15 seconds if the mass of the car is 2500 k

Lyrx [107]

We will solve this question using the second law of motion which states that force is directly equal to the product of mass and acceleration.

$\sf \: F=ma$

Where,

F is force
m is mass
a is acceleration

In our case,

F = ?
m = 2500 kg
a = 20m/s

$\tt \: F_{net} = 2500 \times 20 \\ \tt= 50000$

<em>Thus, The force of 50000 Newton is required to accelerate a car of 2500 kg...~</em>

3 0

3 years ago

Read 2 more answers

What is the rotational speed of the second hand on a clock that measures the seconds?

pickupchik [31]

Explanation:

Below is an attachment containing the solution

5 0

3 years ago

two bumper cars at an amusement park collide together abd get stuck together. assuming that the system of the two bumper cars is

Fiesta28 [93]

The answer to this problem is M1v1-m2v2=(m1+m2)v

7 0

3 years ago