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Elan Coil [88]
3 years ago
13

A 26.3 kg object is traveling at 21.0 m/s north. What average net force is required to bring this object to a stop in 2.60 secon

ds?
Physics
1 answer:
taurus [48]3 years ago
4 0

The average force is -212.4 N

Explanation:

We can solve this problem by using the impulse theorem, which states that the impulse exerted on the object (the product of the force exerted and the time) is equal to the change in momentum of the object:

F \Delta t = m \Delta v

where

F is the net force on the object

\Delta t is the time

m is the mass

\Delta v is the change in velocity

In this problem, we have:

m = 26.3 kg

\Delta v = -21.0 m/s

\Delta t = 2.60 s

Solving for F, we find

F=\frac{m\Delta v}{\Delta t}=\frac{(26.3)(-21.0)}{2.60}=-212.4 N

where the negative sign indicates that the direction of the force is opposite to the motion of the object.

Learn more about force and momentum:

brainly.com/question/9484203

#LearnwithBrainly

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Answer:

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Explanation:

* <em>Lets revise some definitions of graphs</em>

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Velocity-time graph is called speed-time graph.

The vertical axis of a velocity-time graph represents the velocity of the

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In an acceleration time graph y-axis represents the acceleration, and

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The table represents the <em>speed of a car in a northern</em> direction over

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That means the data in the table represent the <em>velocity</em> of the car in a

certain time

Time (s)             Velocity (m/s)  

   0                            5

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   8                            25

   10                           30

Column 1 would be on the x-axis

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Column 2 would be on the y-axis

y-axis represents the velocity

Column 1 should be titled “Time,” and Column 2 should be titled

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3 years ago
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1.90×10²⁰ Electrons

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From the question,

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Substitute these values into equation 1

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Q = 30.45 C.

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1 electron contains 1.6×10⁻¹⁹ C

therefore,

30.45 C = 30.45/1.6×10⁻¹⁹  electrons

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Answer:

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