Answer:
ms⁻¹
Explanation:
Consider the motion of the bullet-block combination after collision
= mass of the bullet = 0.0382 kg
= mass of wooden block = 3.78 kg
= velocity of the bullet-block combination after collision
= spring constant of the spring = 833 N m⁻¹
= Amplitude of oscillation = 0.190 m
Using conservation of energy
Kinetic energy of bullet-block combination after collision = Spring potential energy gained due to compression of spring
ms⁻¹
= initial velocity of the bullet before striking the block
Using conservation of momentum for the collision between bullet and block
ms⁻¹
Answer:
(a). The kinetic energy stored in the fly wheel is 46.88 MJ.
(b). The time is 1.163 hours.
Explanation:
Given that,
Radius = 1.50 m
Mass = 475 kg
Power 
Rotational speed = 4000 rev/min
We need to calculate the moment of inertia
Using formula of moment of inertia
Put the value into the formula
(a). We need to calculate the kinetic energy stored in the fly wheel
Using formula of K.E
Put the value into the formula
(b). We need to calculate the length of time the car could run before the flywheel would have to be brought backup to speed
Using formula of time
Hence, (a). The kinetic energy stored in the fly wheel is 46.88 MJ.
(b). The time is 1.163 hours.
Answer:
2.04 s
Explanation:
v = at + v₀
(-30.0 m/s) = (-9.8 m/s²) t + (-10.0 m/s)
t = 2.04 s
Answer:
Explanation:
a= 7.8i + 6.6j - 7.1k
b= -2.9 i+ 7.4 j+ 3.9k , and
c = 7.6i + 8.8j + 2.2k
r = a - b +c
=7.8i + 6.6j - 7.1k - ( -2.9i + 7.4j+ 3.9k )+ ( 7.6i + 8.8j + 2.2k)
= 7.8i + 6.6j - 7.1k +2.9i - 7.4j- 3.9k )+ 7.6i + 8.8j + 2.2k
= 18.3 i +18.3 j - k
the angle between r and the positive z axis.
cosθ = 18.3 / √18.3² +18.3² +1
the angle between r and the positive z axis.
= 18.3 / 25.75
cos θ= .71
45 degree
