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Marrrta [24]
3 years ago
6

When the atmosphere has too much carbon dioxide in it, the oceans absorb some of it to achieve a new balance. This is an example

of _____. the hydrosphere a geochemical cycle sphere interaction the hydrologic cycle?
Chemistry
2 answers:
Anna35 [415]3 years ago
8 0

sphere interaction is the right answer for odyssey ware


Nana76 [90]3 years ago
3 0
Answer: sphere interaction

The ocean absorbing excess carbon dioxide from the atmosphere in order to maintain balance is an example of sphere interaction. The different spheres like lithosphere, hydrosphere, atmosphere, and geosphere interact with one another naturally to achieve equilibrium in the environment. 

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acetylene gas c2h2 undergoes combustion to produce carbon dioxide and water vapor How many grams of water are produced by the sa
ella [17]

<u>Answer:</u> The amount of water produced in the given reaction is 0.692x grams.

<u>Explanation:</u>

Let us assume that the initial amount of acetylene gas given be 'x' grams. Now, to calculate the number of moles, we will use the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}   ....(1)

Given mass of acetylene = x grams

Molar mass of acetylene = 26 g/mol

Putting values in above equation, we get:

\text{Number of moles of acetylene}=\frac{xg}{26g/mol}=\frac{x}{26}mol

The reaction of combustion of acetylene is given by the equation:

2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O

By Stoichiometry of the reaction:

2 moles of acetylene produces 2 moles of water.

So, \frac{x}{26} moles of acetylene will produce = \frac{2}{2}\times \frac{x}{26}=\frac{x}{26} moles of water.

Now, to calculate the amount of water produced, we use equation 1:

Molar mass of water = 18 g/mol

Moles of water = \frac{x}{26}mol

Putting values in equation 1, we get:

\frac{x}{26}mol=\frac{\text{Mass of water}}{18g/mol}

\text{Mass of water}=\frac{x}{26}\times 18=0.692x grams

8 0
3 years ago
How many molecules of CH4 are in 24.1 g of this compound?
jok3333 [9.3K]

<u>1) find molar mass of CH₄</u>

=12.01+4(1.01)\\\\=16.05\ g/mol

<u>2) determine moles of CH₄</u>

=24.1g\ CH_{4}\ x\ \frac{1\ mol\ CH_{4}}{16.05g\ CH_{4}}\\\\=1.501557632\ mol\ CH_{4}

<u>3) multiply by avogadro's number</u>

=1.501557632\ mol\ CH_{4}\ x\ \frac{6.022\ x\ 10^{23}\ molecules\ CH_{4}}{1\ mol\ CH_{4}} \\\\=9.04238006\ x\ 10^{23}\\\\=9.04\ x\ 10^{23}\ molecules\ CH_{4}

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Glucose, C₂H12O6, is a product of photosynthesis.
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Answer:

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four chiral centers

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