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Marrrta [24]
3 years ago
6

When the atmosphere has too much carbon dioxide in it, the oceans absorb some of it to achieve a new balance. This is an example

of _____. the hydrosphere a geochemical cycle sphere interaction the hydrologic cycle?
Chemistry
2 answers:
Anna35 [415]3 years ago
8 0

sphere interaction is the right answer for odyssey ware


Nana76 [90]3 years ago
3 0
Answer: sphere interaction

The ocean absorbing excess carbon dioxide from the atmosphere in order to maintain balance is an example of sphere interaction. The different spheres like lithosphere, hydrosphere, atmosphere, and geosphere interact with one another naturally to achieve equilibrium in the environment. 

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Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 417 mL .
bixtya [17]

Answer:

m = 1125.9 g.

Explanation:

Hey there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the definition of density as mass divided by volume:

d=\frac{m}{V}

Thus, we solve for the mass in the equation to obtain:

m=d*V

Then, we plug in the values to obtain:

m=2.70g/mL*417mL\\\\m=1125.9g

Regards!

5 0
3 years ago
Natural gas (CH4) has a molar mass of 16.0 g/mole. You started out the day with a tank containing 200.0 g of natural gas. At the
hodyreva [135]

Considering the definition of molar mass, the moles of gas used are 10.625 moles.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Amount of moles used</h3>

Natural gas has a molar mass of 16.0 g/mole.

You started out the day with a tank containing 200.0 g of natural gas.  So, you can apply the following rule of three: If by definition of molar mass 16 grams are contained in 1 mole, 200 grams are contained in how many moles?

amount of moles at the beginning=\frac{200 gramsx1 mole}{16 grams}

<u><em>amount of moles at the beginning= 12.5 moles</em></u>

At the end of the day, your tank contains 30.0 g of natural gas. So, you can apply the following rule of three: If by definition of molar mass 16 grams are contained in 1 mole, 30 grams are contained in how many moles?

amount of moles at the end=\frac{30 gramsx1 mole}{16 grams}

<u><em>amount of moles at the end= 1.875 moles</em></u>

The number of moles used will be the difference between the number of moles used initially and the contents at the end of the day.

moles used= amount of moles at the beginning - amount of moles at the end

moles used= 12.5 moles - 1.875 moles

<u><em>moles used= 10.625 moles</em></u>

<u><em /></u>

Finally, the moles of gas used are 10.625 moles.

Learn more about molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

brainly.com/question/7132033

brainly.com/question/17249726

#SPJ1

3 0
2 years ago
It took 1.5 hours for a bus to go from one city to the next. The bus traveled at an average velocity of 52 mph, west. How far ap
kozerog [31]
The answer is 78 mph

6 0
3 years ago
Read 2 more answers
Which of these is a covalent compound?
OLga [1]
A. NO2 because the elements are both nonmetals.
4 0
3 years ago
Read 2 more answers
A chemical reaction is shown below:
BabaBlast [244]

Answer:

Mass = 8.46 g

Explanation:

Given data:

Mass of water produced = ?

Mass of glucose = 20 g

Mass of oxygen = 15 g

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂     →   6H₂O + 6CO₂

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 20 g/ 180.16 g/mol

Number of moles = 0.11 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 15 g/ 32 g/mol

Number of moles = 0.47 mol

now we will compare the moles of water with oxygen and glucose.

               C₆H₁₂O₆           :            H₂O

                   1                   :              6

                 0.11                :           6/1×0.11 = 0.66

                   O₂               :            H₂O

                   6                   :              6

                 0.47                :           0.47

Less number of moles of water are produced by oxygen thus it will limit the yield of water and act as limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 0.47 mol  ×18 g/mol

Mass = 8.46 g

8 0
3 years ago
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