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Marrrta [24]
3 years ago
6

When the atmosphere has too much carbon dioxide in it, the oceans absorb some of it to achieve a new balance. This is an example

of _____. the hydrosphere a geochemical cycle sphere interaction the hydrologic cycle?
Chemistry
2 answers:
Anna35 [415]3 years ago
8 0

sphere interaction is the right answer for odyssey ware


Nana76 [90]3 years ago
3 0
Answer: sphere interaction

The ocean absorbing excess carbon dioxide from the atmosphere in order to maintain balance is an example of sphere interaction. The different spheres like lithosphere, hydrosphere, atmosphere, and geosphere interact with one another naturally to achieve equilibrium in the environment. 

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Assessment
MakcuM [25]

i didn’t mean to put this opps

4 0
2 years ago
What is a kind of biochemical that does not dissolve in water and makes up cell walls fats oils and waxes?
posledela
Lipids is a kind of biochemical that does not dissolve in water and makes up the cell walls fats oil and waxes
5 0
2 years ago
☝️☝️☝️help☝️☝️☝️!!!!
nataly862011 [7]
8. A. Density is independent of size (an intensive property).
9. B. The highest density is 1786 g/20cm^3, or 89.3 g/cm^3. The least is 512 g/20cm^3, or 25.6 g/cm^3. Therefore, the difference is 89.3 - 25.6, or 63.7 g/cm^3.
10. C. A bottle filled with air weighs less than one filled with marshmallows, because air is less dense than marshmallows.
11. D. The number represents the number of protons in the nucleus of the atom, as well as the atomic number of the element.
12. C. The number represents the atomic mass of the element, which is determined based on the relative abundance of each form of the element.
7 0
3 years ago
How many moles of sand (SiO2) are in 30 g of sand?
anastassius [24]
<h3>Answer:</h3>

0.50 mol SiO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

30 g SiO₂ (sand)

<u>Step 2: Identify Conversions</u>

Molar Mass of Si - 28.09 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of SiO₂ - 28.09 + 2(16.00) = 60.09 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 30 \ g \ SiO_2(\frac{1 \ mol \ SiO_2}{60.09 \ g \ SiO_2})
  2. Multiply/Divide:                  \displaystyle 0.499251 \ mol \ SiO_2

<u>Step 4: Check</u>

<em>Follow sig figs and round. We are given 2 sig figs.</em>

0.499251 mol SiO₂ ≈ 0.50 mol SiO₂

5 0
2 years ago
Read 2 more answers
The density of octane is 0.700 g/cm3.  What is the mass of one liter of octane?
Gelneren [198K]

Answer:

m = 700 g

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Density of octane = 0.700 g/cm³

Volume = 1 L

Mass = ?

Formula:

D=m/v

D= density

m=mass

V=volume

First of all we will convert the volume in cm³ because density is given in g/cm³ unit.

1 L = 1000 cm³

Now we will put the values in formula:

d= m/v

m = v × d

m = 1000 cm³ × 0.700 g/cm³

m = 700 g

5 0
3 years ago
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