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Crank
3 years ago
14

What is the mass of 1.72 moles of BaSO4?

Chemistry
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer: 401.4g

Explanation:

The mass can be calculated by using the following mathematical expression for Moles ,which is:

Moles = Mass / Molar Mass

From the question given, Moles = 1.72, Molar mass of BaSO4 = 233.38g/mol, Mass =?

Making 'Mass' the subject of formula, we get:

Mass = Molar mass x Moles

= 233.38 x 1.72 = 401.4g

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Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.
bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

ΔGr = ΔHr - TΔSr <em>(1)</em>

For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = <u><em>181,66 kJ/mol</em></u>

<u><em /></u>

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = <em><u>0,216 kJ/Kmol</u></em>

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ <em>4. +117,1 kJ/mol</em>

<em></em>

I hope it helps!

5 0
3 years ago
What 3 classes of compounds are elecrolytes
zvonat [6]

Answer:

i believe it is strong acids, strong bases, and salts.

Explanation:

Hope this helps : )

4 0
3 years ago
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l)
stiv31 [10]

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;

For every 1 mole of C₃H₈(g) and 5 moles of  O₂(g) produces  3 moles of  CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);

We represent it in ratio;

C₃H₈(g) : CO₂(g)

1  :     3

What about ;

? (x)   :  1

We cross multiply;

3x = 1 * 1

X = 1/3

We evaluate the same for O₂;

O₂(g) : CO₂(g)

5 :     3

What about

? (x) :     1

3x = 5 * 1

x = 5/3

Learn More:

For more on evaluating moles in chemical reactions check out;

brainly.com/question/13967925

brainly.com/question/13969737

#LearnWithBrainly

7 0
3 years ago
Um.. i dont need help lol
Tasya [4]

Answer:

thats cool mate

Explanation:

hope ya have a good day, im answering just for the points tbh

7 0
3 years ago
Read 2 more answers
A 25.0g tin sample was placed in boiling water at 99.5 C until it had the same temperature. Afterwards, the tin sample was place
MrMuchimi

Answer : The specific heat of tin is, 0.213 J/g.K

Explanation :

Formula used :

q=m\times c\times (T_{final}-T_{initial})

where,

q = amount of heat lost = -399.4 J

c = specific heat capacity of tin = ?

m = mass of tin = 25.0 g

T_{final} = final temperature = 24.5^oC=273+24.5=297.5K

T_{initial} = initial temperature = 99.5^oC=273+99.5=372.5K

Now put all the given values in the above formula, we get:

-399.4J=25.0g\times c\times (297.5-372.5)K

c=0.213J/g.K

Therefore, the specific heat of tin is, 0.213 J/g.K

7 0
3 years ago
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