3 years ago

Drinking energy drinks makes people more aggressive.

Chemistry

1 answer:

ch4aika [34]3 years ago

7 0

Outcome (dependent) variable-drinking energy drinks

Test (independent) variable- more aggressive

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How many moles of hydrogen atoms are there in 120 g of C6H12O6

lys-0071 [83]

Answer: 8.0 moles

Explanation:

0.6661 moles×12 H≈8.0 moles

5 0

3 years ago

Calculate the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L.

Aleonysh [2.5K]

Answer: $15.5^0C$

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 0.987 atm

V = Volume of gas = 12 L

n = number of moles = 0.50

R = gas constant = $0.0821Latm/Kmol$

T =temperature = ?

$T=\frac{PV}{nR}$

$T=\frac{0.987atm\times 12L}{0.0820 L atm/K mol\times 0.50mol}=288.5K=(288.5-273)^0C=15.5^0C$

Thus the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L is $15.5^0C$

8 0

3 years ago

What is the molarity of a solution that contains 0.0345 mol nh4cl in exactly 400 ml of solution?

alexdok [17]

The molarity of a solution is the number of moles of a substance per liter of the solution.
400 mL becomes 0.400 liters
You have 0.0345 moles of ammonium chloride NH4Cl, so take the number of moles over the number of liters to find the answer.
0.0345 moles/0.400 liters = 0.0863 moles/liter
0.0863M = molarity of the solution

4 0

4 years ago

A gas has a volume of 25 ml, at a pressure of 1 atmosphere (1 atm). Increase the volume to 125 ml and the temperature remains co

vekshin1

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2 \\$

Since we're finding the new pressure

$P_2 = \frac{P_1V_1}{V_2} \\$

We have

$P_2 = \frac{25 \times 1}{125} = \frac{25}{125} = \frac{1}{5} = 0.2 \\$

We have the final answer as

Hope this helps you

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3 years ago

The electromagnetic force acts between what

spayn [35]

The electromagnetic is a force that combines the effects of electrical charge and magnetism. The electromagnetic force can either attract or repel the particles on which it acts.

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3 years ago

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