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PilotLPTM [1.2K]
3 years ago
6

Write briefly how oxygen gas is prepared in the industry​

Chemistry
1 answer:
ankoles [38]3 years ago
8 0

by fractional distillation of liquefied air or the use of zeolites to remove carbon dioxide and nitrogen from air or the electrolysis of water

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Which of these following have a positive charges
Over [174]
Talking about ions, a cation has a positive charge. That means a positive charge is gained by an atom that gives out electrons. 
7 0
3 years ago
the density of glycerin is 1.26 g/cm3. How many pounds/foot3 is this ? use the conversion rates of 454g/1 pound and 28,317cm3/1f
lyudmila [28]

Answer:

78.6 lb/ft³  

Step-by-step explanation:

Let's do this in steps.

1. Convert grams to pounds

D = (1.26 g/1 cm³) × (1 lb/454 g)

   = 2.775 × 10⁻³ lb/cm³

2. Convert cubic centimetres to cubic feet

D = (2.775 × 10⁻³ lb/1 cm³) × (28 317cm³/1 ft³)

   = 78.6 lb/ft³

6 0
3 years ago
Using the nernst equation calculate the cell voltage for: fe(s) + cd2+(aq) â fe2+(aq) + cd(s) when the [fe2+] = 0.10 m and [cd2+
Oksi-84 [34.3K]
The Nernst equation is:

E = E° - RTlnK/nF
where
E° is the standard potential voltage
R is the universal gas constant = 8.314 J/mol·K
K is the reaction quotient
n is the number of moles electrons transferred
F is Faraday's constant = 96,500 C/mol e⁻

Let's determine K first. The overall reaction is:

Fe(s) + Cd²⁺(aq) --> Fe²⁺(aq) + Cd(s)
Accounting for aqueous phases only, 
K = [products]/[reactants] = [Fe²⁺]/[Cd²⁺] = 0.10 M/1.4 M = 1/14

From the reactions written, you can see that 2 electrons were transferred. So, n = 2.

Lastly, the value for E⁰ is the sum of individual E⁰ of the reactions.
E⁰ = E⁰cathode - E⁰anode
Cathode reaction: Fe(s) --> 2e + Fe²⁺ (E⁰cathode = 0.44 V)
Anode reaction: Cd²⁺ + 2e --> Cd(s) (E⁰anode = -0.4 V)
Thus,
E⁰ = 0.44 - -0.4 = 0.84 V

Substituting the values (assume T at room temperature = 298 K),
E = 0.84 - (8.314)(298 K)(ln 1/14)/(2)(96,500)
<em>E = 0.87 V</em>
5 0
4 years ago
If 0.25 liters of solution contains 0.030 moles of KOH what is the molarity of the solution?
sdas [7]

Answer:

The molarity of the solution is 0,12 M.

Explanation:

We calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case KOH) in 1000ml of solution (1 liter):

0,25 L solution----- 0,030 moles of KOH

1 L solution----x= (1 L solution x 0,030 moles of KOH)/0,25 L solution

x= 0,12 moles of KOH ---> <em>The solution is 0,12 M</em>

7 0
3 years ago
Which indicator would be the best to use if 0. 050 m benzoic acid ( k a = 6. 6 × 10 –5) is titrated with 0. 050 m naoh?
Alexus [3.1K]

I would say Phenolphthalein

7 0
2 years ago
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