1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lutik1710 [3]
3 years ago
14

A chemical reaction in which atoms have their oxidation number (oxidation state) changed.

Chemistry
1 answer:
GaryK [48]3 years ago
4 0

Answer:

An oxidation-reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between two species. An oxidation-reduction reaction is any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.

Explanation:

You might be interested in
How much heat (in kj) is released when 3.600 mol naoh(s) is dissolved in water? (the molar heat of solution of naoh is â445.1 kj
Fantom [35]
<span>-1602 kj

Sauce:me

Your welcome
</span>
8 0
3 years ago
Read 2 more answers
a water sample is found to have a cl- content of 100ppm as nacl what is the concentration of chloride in moles per liter
ladessa [460]

Answer:

The concentration of chloride ion is 2.82\times10^{-3}\;mol/L

Explanation:

We know that 1 ppm is equal to 1 mg/L.

So, the Cl^- content 100 ppm suggests the presence of 100 mg of Cl^- in 1 L of solution.

The molar mass of Cl^- is equal to the molar mass of Cl atom as the mass of the excess electron in Cl^- is negligible as compared to the mass of Cl atom.

So, the molar mass of Cl^- is 35.453 g/mol.

Number of moles = (Mass)/(Molar mass)

Hence, the number of moles (N) of Cl^- present in 100 mg (0.100 g) of Cl^- is calculated as shown below:

N=\frac{0.100\;g}{35.453\;g/mol}=2.82\times 10^{-3}\;mol

So, there is 2.82\times10^{-3}\;mol of Cl^- present in 1 L of solution.

5 0
3 years ago
Which of the following is the best explanation for why it is important to follow lab safety guidelines
____ [38]

Answer:

B

Explanation:

The main aim of lab rules is to minimize the no of accidents

5 0
3 years ago
Which 2 elements when combined NOT alloys?
Volgvan

Answer:

Oxygen and sulfur

Explanation:

Alloys consist of metals fused together sometimes with additional components, such as carbon, to prevent metals from corrosion.

Oxygen and sulfur are two compounds consisting of non-metal atoms, O and S. Combining oxygen with sulfur would actually produce sulfur dioxide, a gas, in contrast to a metallic substance that is fused with some other metal or carbon.

That's the reason why combination of sulfur and oxygen wouldn't produce an alloy: it would produce a gas.

6 0
3 years ago
Seagrasses are flowering plants which grow in the photic zones of marine environments. Which factor would be a biotic limiting f
olga2289 [7]

Answer:

density of animal populations

Hope this helped

6 0
3 years ago
Other questions:
  • The following reaction shows sodium carbonate reacting with calcium hydroxide.
    7·1 answer
  • Element x reacts with oxygen to produce x2o3 in an experiment it is found that 1.0000 g of x produces 1.1xxx g of x2o3 what is t
    13·1 answer
  • if a sample of gas at 25.2 c has a volume of 536mL at 637 torr, what will its volume be if the pressure is increased to 712 torr
    15·1 answer
  • Calculate the ph and the poh of an aqueous solution that is 0.030 m in hcl(aq) and 0.070 m in hbr(aq) at 25°c.
    14·1 answer
  • 3
    7·1 answer
  • One mole of an ideal gas, for which CV,m = 3/2R, initially at 298 K and 1.00 × 105 Pa undergoes a reversible adiabatic compressi
    15·1 answer
  • What is a limitation of using a chemical formula, such as C6H12O6, to represent a compound?
    13·1 answer
  • Identify the outer electron configurations for the (a) alkali metals, (b) alkaline earth metals, (c) halogens, (d) noble gases.
    10·1 answer
  • Cuales son las del ciclo de el fósforo
    8·1 answer
  • Can someone please help? This is really hard!!
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!