Answer:
The answer to your question is Concentration = 0.54 mmol/L
Explanation:
Data
Barium acetate = BaCH₃CO₂
mass = 81.4 μmol
volume = 150 ml
concentration = mmol / L
Process
1.- Convert the μmol to mmol
1000 μmol ------------------ 1 mmol
81.4 μmol ----------------- x
x = (81.4 x 1) / 1000
x = 0.0814 mmol of BaCH₃CO₂
2.- Convert the volume to liters
1000 ml -------------------- 1 l
150 ml --------------------- x
x = (150 x 1) / 1000
x = 0.15 l
3.- Calculate the concentration
Concentration = 0.0814 / 0.15
= 0.54 mmol/L
