Answer:(a) 50 N
(b)38.34 N
Explanation:
Given
Maximum tension(T) in line 50 N
(a)If line is moving up with constant velocity i.e. there is no acceleration
This will happen when Tension is equal to weight of Fish
T-mg=0
T=mg
Maximum weight in this case will be 50 N
(b)acceleration of magnitude
T-mg=ma
m=3.91
Therefore weight is
Answer:
532 millimeters of mercury
Explanation:
In order to convert the pressure from atm to millimeters of mercury (mm Hg), we should remind the conversion factor between the two units:
1 atm = 760 mm Hg
Therefore, we can solve the problem by setting up the following proportion:
Solving for x, we find
A) The net force on the motorbike is 205.9 N
B) The acceleration of the motorbike is
C) The final speed is 5.2 m/s
D) The elapsed time is 3.80 s
Explanation:
A)
There are two forces acting on the motorbike:
- The applied force, F = 250 N, forward
- The frictional force, , backward
The frictional force can be written as
where
is the coefficient of kinetic friction
is the mass of the motorbike
is the acceleration of gravity
Therefore the net force is given by
And substituting, we find
2)
The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:
where
m is the mass
a is the acceleration
In this problem, we have
is the net force
m = 150 kg is the mass
Solving for a, we find the acceleration:
C)
Since the motion of the motorbike is a uniformly accelerated motion, we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For this motorbike, we have:
u = 0 (it starts from rest)
s = 350 m
Solving for v,
4)
For this part of the problem, we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the elapsed time
Here we have:
v = 5.2 m/s
u = 0
Solving for t, we find
Learn more about Newton's laws of motion and accelerated motion:
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