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4 years ago

I need to know how to do this problem I am completely stuck

Mathematics

1 answer:

Vinil7 [7]4 years ago

6 0

This is FACTORISATION.

To solve this problem we have to find the common terms in this equation.

Firstly, between the 5x³ and 10x² the like terms are 5. But the question is, where did the 5 come from? Well in Factorisation, we have to find the HCF between two terms. Here is my answer:

5x³+10x²-25x-50

5x²(1x+2)-25(x+2)-› HCF of 5 and 10 is 5, HCF of 25 and 50 is 25

(1x+2)(5x²-25)-› Add the numbers from the brackets and the numbers outside the brackets.

SO THE ANSWER IS (1x+2)(5x+25)

HOPE THIS HELPS!!!! ;)

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3 years ago

Valerie drives to and from work 5 days a week. the distance from her home to work is 6 miles. over the course of 5 days, her car

kaheart [24]

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5 0

3 years ago

Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes

yaroslaw [1]

Answer:

$\frac{y^{2}}{25}-\frac{x^{2}}{3}=1$

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: $(0,-\sqrt{28}),(0,\sqrt{28})$

eje conjugado = $2\sqrt{3}$

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

$\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1$

de los focos podemos obtener que:

$c=\sqrt{28}$

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

$b=\sqrt{3}$

podemos utilizar la siguiente fórmula para obtener a:

$c^{2}-a^{2}=b^{2}$

si despejamos a en la ecuación obtenemos lo siguiente:

$a=\sqrt{c^{2}-b^{2}}$

ahora podemos sustituir los valores:

$a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}$

$a=\sqrt{28-3}$

$a=\sqrt{25}$

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

$\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1$

$\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1$

$\frac{y^{2}}{25}+\frac{x^{2}}{3}=1$

si graficamos la hipérbola, queda como en el documento adjunto.

7 0

3 years ago

the perimeter of a triangle is 59 in. The longest side is 11in. longer than the medium side, and the medium side is 3in longer t

Nataly_w [17]

Let the length of shortest side be - x
length of medium side - x +3
length of longest side - x +3 + 11
so , according to question
=> x + x +3 + x +3 + 11 = 59
=> x + x +x + 3 + 3 + 11 = 59
=> 3x = 59 - 17
=> 3 x = 42
=> x = 42/3
=> x = 14
Shortest side = x = 14
medium side = x + 3 = 14+3 = 17
longest side = x + 3 +11 = 14 + 3 + 11 = 28

4 0

3 years ago

What is the solution set of 7x 2 + 3x = 0? {0, 3/7} {0, -3/7} {0, -4/7}

34kurt

X(7x+3)=0
x=0
or
7x=-3
x=-3/7

so,
(0,0) or (-3/7,0)

5 0

3 years ago