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pishuonlain [190]
3 years ago
12

For each example, identify if the food contains mostly saturated or unsaturated fatty acids.

Chemistry
1 answer:
dedylja [7]3 years ago
3 0

Answer:

1. Vegetable oil, which is a liquid at room temperature, is used in making cake batter. <u>Unsaturated</u>

2. Chocolate, which is solid at room temperature, is derived from a seed. <u>Saturated</u>

3. Butter<u>,</u> which is a solid at room temperature, is often used in cooking. <u>Saturated</u>

4. The oil inside flaxseed oil pills is liquid at room temperature. <u>Unsaturated</u>

Explanation:

Saturated fats are those kinds of fat that do not have a double bond between their carbon atoms when represented structurally. At room temperature, they tend to assume the solid-state, and they are mostly obtained from animal sources. Unsaturated fats do have a minimum of one double bond between their carbon atoms and tend to assume the liquid phase. They are mostly obtained from plant sources.<em> </em>

1. Vegetable oil is obtained from a plant source and is, therefore, unsaturated fat.

2. Chocolate even though it comes from cocoa is solid at room temperature and is mostly comprised of saturated fat.

3. Butter a solid at room temperature is mostly made up of saturated fat and is sourced from animals.

4. Flaxseed oil obtained from a plant source is mostly unsaturated fat.

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A 100 g sample of potassium chlorate, KCIO3(s), is completely decomposed by heating:
Mama L [17]
Explanation:
In order to be able to calculate the volume of oxygen gas produced by this reaction, you need to know the conditions for pressure and temperature.
Since no mention of those conditions was made, I'll assume that the reaction takes place at STP, Standard Temperature and Pressure.
STP conditions are defined as a pressure of
100 kPa
and a temperature of
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∘
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. Under these conditions for pressure and temperature, one mole of any ideal gas occupies
22.7 L
- this is known as the molar volume of a gas at STP.
So, in order to find the volume of oxygen gas at STP, you need to know how many moles of oxygen are produced by this reaction.
The balanced chemical equation for this decomposition reaction looks like this
2
KClO
3(s]
heat
×
−−−→
2
KCl
(s]
+
3
O
2(g]
↑
⏐
⏐
Notice that you have a
2
:
3
mole ratio between potassium chlorate and oxygen gas.
This tells you that the reaction will always produce
3
2
times more moles of oxygen gas than the number of moles of potassium chlorate that underwent decomposition.
Use potassium chlorate's molar mass to determine how many moles you have in that
231-g
sample
231
g
⋅
1 mole KClO
3
122.55
g
=
1.885 moles KClO
3
Use the aforementioned mole ratio to determine how many moles of oxygen would be produced from this many moles of potassium chlorate
1.885
moles KClO
3
⋅
3
moles O
2
2
moles KClO
3
=
2.8275 moles O
2
So, what volume would this many moles occupy at STP?
2.8275
moles
⋅
22.7 L
1
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6 0
3 years ago
What is the density of an object that has a mass of 28.1g and a volume of 96.2mL? Select the correct answer below: 0.292g/mL 270
kakasveta [241]

Answer:

0.292 g/mL.

Explanation:

From the question given above, the following data were obtained:

Mass of object = 28.1 g

Volume of object = 96.2 mL

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Density of an object is simply defined as the mass of the object per unit volume of the object. Mathematically, it can be expressed as:

Density = mass / volume

With the above formula, we can obtain the density of the object as follow:

Mass of object = 28.1 g

Volume of object = 96.2 mL

Density of object =..?

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Density = 28.1 / 96.2

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kolezko [41]

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