Two categories based on a medium. "Hint" needs assistance

If liquid water is exposed to normal atmospheric pressure, what needs to change in order to change its state of matter?

inn [45]

Answer: Option (b) is the correct answer.

Explanation:

State of a substance changes when heat is provided to a substance.

This is because when we heat water then intermoleclar forces present within its molecules tend to break down. Due to this molecules start to move away from each other.

As a result, kinetic energy of molecules increases and they collide rapidly. Hence, solid state of water changes into liquid state and upon excessive heating liquid state of water changes into vapor state.

Thus, we conclude that temperature of water needs to change in order to change its state of matter.

6 0

3 years ago

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A 256 mL sample of HCl gas is in a flask where it exerts a force (pressure) of 67.5 mmHg. What is the pressure of the gas if it

Effectus [21]

Answer:

The pressure in the new flask would be $128\; \rm mmHg$ if the $\rm HCl$ here acts like an ideal gas.

Explanation:

Assume that the $\rm HCl$ sample here acts like an ideal gas. By Boyle's Law, the pressure $P$ of the gas should be inversely proportional to its volume $V$ .

For example, let the initial volume and pressure of the sample be $V_1$ and $P_1$ . The new volume $V_2$ and pressure $P_2$ of this sample shall satisfy the equation: $P_1 \cdot V_1 =P_2 \cdot V_2$ .

In this question,

The initial volume of the gas is $V_1= 256\; \rm mL$ .
The initial pressure of the gas is $P_1 = 67.5\; \rm mmHg$ .
The new volume of the gas is $V_2 = 135\; \rm mL$ .

The goal is to find the new pressure of this gas, $P_2$ .

Assume that this sample is indeed an ideal gas. Then the equation $P_1 \cdot V_1 =P_2 \cdot V_2$ should still hold. Rearrange the equation to separate the unknown, $P_2$ . Note: make sure that the units for $V_1$ and $V_2$ are the same before evaluating. That way, the unit of

$\begin{aligned} & P_2\\ &= \frac{P_1 \cdot V_1}{V_2} \\ &= \frac{256\; \rm mL \times 67.5\; \rm mmHg}{135\; \rm mL} \\ & \approx 128\; \rm mmHg\end{aligned}$ .

3 0

3 years ago

Estimate the molar mass of a gas that effuses at 1.6 times the effusion rate of CO2

Vlada [557]

To estimate the molar mass of the gas, we use Graham's law of effusion. This relates the rates of effusion of gases with their molar mass. We calculate as follows:

r1/r2 = √(m2/m1)

where r1 would be the effusion rate of the gas and r2 is for CO2, M1 is the molar mass of the gas and M2 would be the molar mass of CO2 (44.01 g/mol)

r1 = 1.6r2

1.6 = √(44.01 / m1)
m1 = 17.19 g/mol

7 0

3 years ago

4. How does the kinetic theory of gases explain the weather changes happening in the troposphere? You can also research on the I

uranmaximum [27]

According to the kmt pressure is directly proportional to the number of collision between particles

4 0

3 years ago

Read 2 more answers

Please someone do this for me. Im really stuck

Alex_Xolod [135]

Is it me or is the picture not loading

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