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V125BC [204]
2 years ago
8

Two categories based on a medium. "Hint" needs assistance

Chemistry
1 answer:
Margarita [4]2 years ago
5 0

Answer:

lololz

Explanation:

 

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How many moles of O2 are produced when 0.425 mol of KO2 reacts in this fashion
Oksi-84 [34.3K]
The chemical reaction is expressed as:

<span> 4KO2+2CO2→2K2CO3+3O2 
</span>
We are given the amount of KO2 to be used in the reaction. This will be the starting point of our calculations. We do as follows:

0.425 mol KO2 ( 3 mol O2 / 4 mol KO2 ) = 0.319 mol O2 produced

Hope this answers the question. Have a nice day.
4 0
3 years ago
You have a solution that is 18.5% (v/v) methyl alcohol. If the bottle contains 1.64 L of solution, what is the volume (V) in mil
Juliette [100K]

Answer:

303.4 millimeters

Explanation:

Just multiply 1.64 by 0.185. then convert that answer to millimeters

7 0
2 years ago
An atom of oxygen has atomic of 8 and a mass number of 18. How many of each type of subatomic particle doe it contain?
Tju [1.3M]
An atom of Oxygen. Contains:

Protons = 8
Electrons = 8

Neutrons = Mass number - Number of protons = 18 - 8 = 10

Neutrons = 10.
7 0
3 years ago
One of the emission spectral lines for Be3+ has a wavelength of 253.4 nm for an electronic transition that begins in the state w
4vir4ik [10]

Answer:

4

Explanation:

Relationship between wavenumber and Rydberg constant (R) is as follows:

wave\ number=R\times Z^2\frac{1}{n_1^2} -\frac{1}{n_1^2}

Here, Z is atomic number.

R=109677 cm^-1

Wavenumber is related with wavelength as follows:

wavenumber = 1/wavelength

wavelength = 253.4 nm

wavenumber=\frac{1}{253.4\times 10^{-9}} \\=39463.3\ cm^{-1}

Z fro Be = 4

39463.3=109677\times 4^2(\frac{1}{n_1^2} -\frac{1}{5^2})\\39463.3=109677\times 16(\frac{1}{n_1^2} -\frac{1}{5^2})\\n_1=4

Therefore, the principal quantum number corresponding to the given emission is 4.

6 0
3 years ago
Who was the first to state the concept of an atom
marin [14]
Democritus, a Greek philosopher, first developed the idea of atoms (around 460 B.C., I believe).
Hope this helps!
6 0
3 years ago
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