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gregori [183]
3 years ago
14

Question 2: you have two systems: 1) solid gold and water 2) solid sodium and waterWhich one can spontaneously release energy an

d why?
Chemistry
1 answer:
Valentin [98]3 years ago
7 0

Hey there!

Solid Sodium and water will react spontaneously and release energy.  This is based on the reactivity series. Sodium is a highly reactive metal and hence, it is placed at the top of the reactivity series. This is because it loses its outermost electron very readily. When it comes in contact with water, it reacts with it violently to form sodium hydroxide and hydrogen gas. This reaction is exothermic and hence, accompanied with a release of energy.  Gold lies at the bottom of the reactivity series as it is very stable and does not give away its outermost electrons easily. Therefore, when it comes in contact with water, there is no reaction and no release of energy.

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I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol
galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = \Delta H_f_{(I_2)}=62.438 kJ/mol

Enthalpy of formation of chlorine gas = \Delta H_f_{(Cl_2)}=0 kJ/mol

Enthalpy of formation of ICl gas = \Delta H_f_{(ICl)}=17.78 kJ/mol

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]

=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol

Enthaply change when 1.62 moles of iodine gas recast:

\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ

Entropy of the surrounding = \Delta S^o_{surr}=\frac{\Delta H}{T}

=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0
3 years ago
which event would be less widely visible from Earth: a partial lunar eclipse or a total lunar eclipse? explain please
adell [148]

Answer:

I had the same question and I put a total lunar eclipse.

Explanation:

A total lunar eclipse would be less widely visible because, in a partial lunar eclipse the moon only has to partly be in the Earth's shadow.

I don't know if this is helpful or not, but this is what I put if you still needed it.

Still stuck? Get 1-on-1 help from an expert tutor now.

6 0
2 years ago
Your computer is an example of which type of energy? Question options: Nuclear Kinetic Light All of the above
xz_007 [3.2K]

<u>Answer</u>:  Light

<em>Computer is an example of light energy which is the third option out of the given four choices. </em>

<u>Explanation:</u>

We know how a computer works it takes in <em>the electrical energy</em> and does a <em>lot of mathematical mechanical work</em> and for giving answers. It uses a screen on which light blinks in pattern such that it represents letters or mathematical numbers or expressions.

Hence by using this statement we can say <em>computer converts electrical energy into light energy. </em>

4 0
3 years ago
How many molecules of water can fit in one teaspoon?
34kurt
About 5 millimeters which weighs about 5 grams. Hope this helps! ^-^

4 0
4 years ago
A procedure calls for the bromination of 12 mmol of trans‑cinnamic acid with 12 mmol of Br 2 in glacial acetic acid solvent. Sel
SashulF [63]

Answer: The yield of dibromide product will be approximately one‑half of the expected yield.

Explanation:

6 0
3 years ago
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