Answer:
The molar mass of the gas is 99.4 g/mol
Explanation:
Ideal gas law PV=nRT. P=155.3 T=127+273= 400K V=25.0 Gas constant=8.314 Now substiture the values into the equation n=PV/RT
n= (155.5kPa x 25.0mL x 1l/1000mL)/ 8.312l*KPa/mol*K x 400K
n= 0.001167 mol
Molar mass= Mass/ Number of moles
= 0.116g /0.001167 mol
= 99.4 g/mol
Answer:
See explanation
Explanation:
Ga is in group 13 hence it must loose three electrons to form Ga^3+ in order to achieve the noble gas configuration because it has three electrons on its outermost shell.
O is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form O^2- since oxygen has six electrons on its outermost shell.
Br in group 17 has seven electrons in its outermost shell hence it must form Br^- (gain one electron) in order to attain the noble gas configuration.
P in group 15 must accept three electrons and form P^3- in order to attain the noble gas configuration since it has five electrons on its outermost shell.
S is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form S^2- since sulphur has six electrons on its outermost shell.
Mg in group 2 has two electrons on its outermost shell and must loose both to attain the noble gas configuration forming Mg^2+.
Al is in group 13 hence it must loose three electrons to form Al^3+ in order to achieve the noble gas configuration because it has three electrons on its outermost shell.
Se is in group 16 hence it must accept two electrons in order to attain the noble gas configuration to form Se^2- since selenium has six electrons on its outermost shell.
Lithium is in group 1 and must loose its only outermost electron in order to attain the noble gas configuration to form Li^+.
Rb is in group 1 and must loose its only outermost electron in order to attain the noble gas configuration to form Rb^+.
As in group 15 must accept three electrons and form As^3- in order to attain the noble gas configuration since it has five electrons on its outermost shell.
I in group 17 has seven electrons in its outermost shell hence it must form I^- (gain one electron) in order to attain the noble gas configuration.
a hypothesis is an idea or explanation that you then test through study and experimentation
Answer:
6
Explanation:
The atomic number for phosphorous is 15, meaning that it has 15 electrons (and protons). The first and second shells would be filled up with 2 and 8 electrons respectively, leaving 5 which goes on the third shell, which is also the valence shell, meaning phosphorous has 5 valence electrons.
Since the atomic number of sulfur is 16, the first and second shells are also filled up with 2 and 8 electrons respectively, leaving 6 to be on the third shell, the valence shell. Hence, sulfur has 6 valence electrons.
Answer:
I think C (Might not be true)
Explanation:
