Question

How many moles of NO₂ would be required to produce 2.30 moles of HNO₃ in the presence of excess water in the following chemical reaction?
3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

Answer 1

Answer:

Stoichiometric Calculation:

3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

2 moles of HNO₃ is produced from 3 moles of NO₂.

Therefore, By unitary method:

2.30 moles of HNO₃ produced from the moles of NO₂ = $\dfrac{3}{2} \times 2.30 = \bf{3.45 mol}$