How many moles of NO₂ would be required to produce 2.30 moles of HNO₃ in the presence of excess water in the following chemical

Question

3 years ago

13

reaction?
3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

1 answer:

kow [346] · Answer 1 · 2022-06-12T18:01:46+03:00

kow [346]3 years ago

6 0

Answer:

Stoichiometric Calculation:

3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

2 moles of HNO₃ is produced from 3 moles of NO₂.

Therefore, By unitary method:

2.30 moles of HNO₃ produced from the moles of NO₂ = $\dfrac{3}{2} \times 2.30 = \bf{3.45 mol}$