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Doss [256]
3 years ago
15

Hardness of metals can be decreased by: (a) adding interstitial alloying elements (b) making glassy metals through extremely hig

h cooling rates (c) annealing using slow cooling from high temperatures (d) cold-working or deforming at low temperatures
Chemistry
1 answer:
n200080 [17]3 years ago
4 0

Answer:

Option c is correct

Explanation:

The interstitial alloy elements occupy the free spaces in the metal structure and improve the symmetry of the crystalline network, for this reason this type of elements increases the hardness of the metal.

Vitreous metals are called that because they are formed by high cooling rates and form amorphous structures such as glass, such structures contain packaging of atoms of different sizes, which decreases the free spaces in the metal structure and this increases their hardness.

In option d, the work at low temperatures causes the vibrations of the atoms to decrease and compact, this makes many metals brittle but in general increases their hardness.

Option c is correct because in annealing the metal is heated to the austenization temperature, that is, the temperature at which a structural change occurs, which destroys its crystalline network and then slowly cools to maintain this structure change and by causing this disorder, the spaces between the atoms increase and the hardness of the metal decreases.

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3 0
2 years ago
Which solution has the same boiling point as 0.25 mol CaCl2 dissolved in 1000 g water?
Rufina [12.5K]
The boiling point of water at 1 atm is 100 degrees celsius. However, when water is added with another substance the boiling point of it rises than when it is still a pure solvent. This called boiling point elevation, a colligative property. The equation for the boiling point elevation is expressed as the product of the ebullioscopic constant (0.52 degrees celsius / m) for water), the vant hoff factor and the concentration of solute (in terms of molality). 

 ΔT(CaCl2) = i x K x m = 3 x 0.52 x 0.25 = 0.39 °C
<span> ΔT(Sucrose) = 1 x 0.52 x 0.75 = 0.39 </span>°C<span>
</span><span> ΔT(Ethylene glycol) = 1 x 0.52 x 1 = 0.52 </span>°C<span>
</span><span> ΔT(CaCl2) = 3 x 0.52 x 0.50 = 0.78 </span>°C<span>
</span><span> ΔT(NaCl) = 2 x 0.52 x 0.25 = 0.26 </span>°C<span>
</span>
Thus, from the calculated values, we see that 0.75 mol sucrose dissolved on 1 kg water has the same boiling point with 0.25 mol CaCl2 dissolved in 1 kg water.

5 0
3 years ago
Intravenous saline solutions are often administered to patients in the hospital. Normal saline solution containers has a concent
zalisa [80]

0.02 mol NaCl

Explanation:

(0.2M NaCl)×(0.10 L) = 0.02 mol NaCl

8 0
3 years ago
choose a reasonable mechanism for the formation of cyclohexylbenzene from the reaction of benzene, cyclohexene, and sulfuric aci
vagabundo [1.1K]

The reasonable mechanism for the formation of cyclohexylbenzene from the reaction of benzene, cyclohexene, and sulfuric acid is Friedel craft alkylation.

In the Friedel craft alkylation cyclohexylbenzene from the reaction of benzene, cyclohexene, and sulfuric acid. in the first step the cyclohexene produced carbocation in the presence of sulfuric acid by protonation. in the second step the `the carbocation undergoes nucleophilic by the benzene ring and produced cyclohexylbenzene. this is the mechanism  followed in the formation of the cyclohexylbenzene by the Friedel craft alkylation.

Thus, The reasonable mechanism for the formation of cyclohexylbenzene from the reaction of benzene, cyclohexene, and sulfuric acid is Friedel craft alkylation.

To learn more about Friedel craft alkylation here

brainly.com/question/17330247

#SPJ4

4 0
1 year ago
Work done after rutherford's gold foil experiment demonstrated that the nucleus contained ________.
shutvik [7]
Protons and neutrons

hope this helps 
5 0
3 years ago
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