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Doss [256]
3 years ago
15

Hardness of metals can be decreased by: (a) adding interstitial alloying elements (b) making glassy metals through extremely hig

h cooling rates (c) annealing using slow cooling from high temperatures (d) cold-working or deforming at low temperatures
Chemistry
1 answer:
n200080 [17]3 years ago
4 0

Answer:

Option c is correct

Explanation:

The interstitial alloy elements occupy the free spaces in the metal structure and improve the symmetry of the crystalline network, for this reason this type of elements increases the hardness of the metal.

Vitreous metals are called that because they are formed by high cooling rates and form amorphous structures such as glass, such structures contain packaging of atoms of different sizes, which decreases the free spaces in the metal structure and this increases their hardness.

In option d, the work at low temperatures causes the vibrations of the atoms to decrease and compact, this makes many metals brittle but in general increases their hardness.

Option c is correct because in annealing the metal is heated to the austenization temperature, that is, the temperature at which a structural change occurs, which destroys its crystalline network and then slowly cools to maintain this structure change and by causing this disorder, the spaces between the atoms increase and the hardness of the metal decreases.

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C+ O2 --&gt; CO2 +60kJ <br> is the reaction exothermic or<br> endothermic?
igomit [66]

Answer:

exothermic

Explanation:

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The number of bonds in nitrogen molecule is:
Afina-wow [57]

Answer:

3 is the answer.

Explanation:

Nitrogen atoms will form three covalent bonds (also called triple covalent) between two atoms of nitrogen because each nitrogen atom needs three electrons to fill its outermost shell.

8 0
3 years ago
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Name the cycloalkanes with molecular formula c6h12 that have a 3-membered ring and two substituents.
Tanzania [10]

Answer:

1-ethyl-2-methyl cyclopropane.

Explanation:

  • The structure of the molecule will be as shown in the attached image.
  • The molecular formula of the compound is C₆H₁₂.
  • It has 3 membered ring with 3 C atoms and two substituents one of them with one C atom (methyl) and the other with 2 C atoms (ethyl).
  • The ring consist of 3 C atoms, so its name is cyclo propane.
  • We numbering the atoms of the ring that give the ethyl substituent the low no. (1) and then methyl group take no. (2).
  • <em>Thus, the name of the compound is 1-ethyl-2-methyl cyclopropane.</em>

3 0
3 years ago
Which instrument is used to measure mass?
alexdok [17]

Answer:

Balance

Explanation:

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7 0
3 years ago
Calculate ΔG o for the following reaction at 25°C: 3Mg(s) + 2Al3+(aq) ⇌ 3Mg2+(aq) + 2Al(s) Enter your answer in scientific notat
larisa [96]

Answer:

-3.7771 × 10² kJ/mol

Explanation:

Let's consider the following equation.

3 Mg(s) + 2 Al³⁺(aq) ⇌ 3 Mg²⁺(aq) + 2 Al(s)

We can calculate the standard Gibbs free energy (ΔG°) using the following expression.

ΔG° = ∑np . ΔG°f(p) - ∑nr . ΔG°f(r)

where,

n: moles

ΔG°f(): standard Gibbs free energy of formation

p: products

r: reactants

ΔG° = 3 mol × ΔG°f(Mg²⁺(aq)) + 2 mol × ΔG°f(Al(s)) - 3 mol × ΔG°f(Mg(s)) - 2 mol × ΔG°f(Al³⁺(aq))

ΔG° = 3 mol × (-456.35 kJ/mol) + 2 mol × 0 kJ/mol - 3 mol × 0 kJ/mol - 2 mol × (-495.67 kJ/mol)

ΔG° = -377.71 kJ = -3.7771 × 10² kJ

This is the standard Gibbs free energy per mole of reaction.

5 0
3 years ago
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