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Ymorist [56]
3 years ago
14

Which of the following solids would possess the lowest melting point?

Chemistry
2 answers:
saul85 [17]3 years ago
4 0
The melting points of the compounds from the choices are listed below:

a. C25H52 -> +47 to +56 degrees celsius 

b. Hg -> -38.83 degrees celsius

c. CaCl2 -> +772 degrees celsius

d. CuO -> +1326 degrees celsius

It is evident from the listed melting points above that mercury (Hg) has the lowest melting point. This is why mercury is liquid at room temperature. 
vovikov84 [41]3 years ago
4 0

Answer:  Hg

Explanation:  As we know that in case of hydrocarbons, as the size increases, vander waal forces become strong thus attract each other with a strong tendency thus C_{25}H_{52} is solid at room temperature. Its melting point is approximately 50°C.

Mercury is the only metal which exist as liquid at room temperature thus iy has lower melting point of  -38.83 °C.

CaCl2 is and CuO are closely packed solids and thus have high melting point. The former one has melting point of 772 °C and th latter one has melting point of 1326°C.

Thus Mercury has lowest melting point out of the given options.

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Answer:

45.3°C

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 82KPa

Initial temperature (T1) = 26°C

Final pressure (P2) = 87.3KPa.

Final temperature (T2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K.

Step 3:

Determination of the new temperature of the gas. This can be obtained as follow:

P1/T1 = P2/T2

82/299 = 87.3/T2

Cross multiply to express in linear form

82 x T2 = 299 x 87.3

Divide both side by 82

T2 = (299 x 87.3) /82

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Step 4:

Conversion of 318.3K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 318.3K

T(°C) = 318.3 – 273

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Therefore, the new temperature of the gas in th tire is 45.3°C

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