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Allushta [10]
3 years ago
7

"calculate the h+ in a solution that has a ph of 8.73"

Chemistry
1 answer:
alexdok [17]3 years ago
8 0
The  H+   in  a  solution  that  has  a Ph  of  8.73   is   calculate    as  follows

Ph is always =   -  log  (H+)

H+  =    10^-Ph

H+  is  therefore  =  10 ^-  8.73
H+  =  1.86  x10^-9  M
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Describe how ionic compounds form crystals
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An ionic<span> crystal consists of </span>ions<span> bound together by electrostatic attraction. The arrangement of </span>ions<span> in a regular, geometric structure is called a crystal lattice. Examples of such </span>crystals<span> are the alkali halides, which include: potassium fluoride </span>
8 0
3 years ago
Find the density of a substance with a mass of 45 grams and a volume of 9
Over [174]

Density = mass / volume

Density = (45g) / (9 [volume units])

Density = 5g / [volume unit]

There was no specification on the units of volume.  However, whatever it may be, just replace the square brackets with the value and your units will be correct.

6 0
3 years ago
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andrew11 [14]

Answer:

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6 0
2 years ago
Convert 1.248×1010 g to each of the following units.
Leona [35]

Answer:

a) 1.248 x 10⁷ kg

b) 1.248 x 10⁴ Mg

c) 1.248 x 10¹³ mg

d) 1.248 x 10⁴ ton

Explanation:

a) Since 1000 g = 1 kg we can convert grams to kg by multiplyig any given quantity in grams by the conversion factor ( 1 kg / 1000 g):

1.248 x 10¹⁰ g * (1 kg / 1000 g) = 1.248 x 10⁷ kg

b) Since 1 Mg = 1 x 10⁶ g, the conversion factor will be ( 1 Mg / 1 x 10⁶ g):

1.248 x 10¹⁰ g * (  1 Mg / 1 x 10⁶ g) = 1.248 x 10⁴ Mg

c) Since 1 mg = 1 x 10⁻³ g, the conversion factor will be ( 1 mg / 1 x 10⁻³ g):

1.248 x 10¹⁰ g ( 1 mg / 1 x 10⁻³ g) = 1.248 x 10¹³ mg

d) Since 1 metric ton = 1000 kg and 1000 g = 1 kg, we can use these conversions factors: ( 1 kg / 1000 g) and (1 ton / 1000 kg):

1.248 x 10¹⁰ g * ( 1 kg / 1000 g) * ( 1 ton / 1000 kg) = 1.248 x 10⁴ ton

8 0
3 years ago
Complete combustion of a 17.12mg sample of xylene In oxygen yielded 56.77mg
Veronika [31]

Xylene moles =\frac{17.12}{106.16×1000}=0.00016moles=

106.16×1000

17.12

=0.00016moles

Moles of CO_2 =\frac{56.77}{44.01×1000}=0.0013CO

2

=

44.01×1000

56.77

=0.0013

Moles of H_2O= =\frac{14.53}{18.02×1000}=0.0008H

2

O==

18.02×1000

14.53

=0.0008

Moles ratios

\frac{0.0013}{0.0008}=1.625

0.0008

0.0013

=1.625

\frac{0.0008}{0.0008}=1

0.0008

0.0008

=1

Hence molecular fomula

The empirical formula is C 4H 5.

The molecular formula C8H10

8 0
2 years ago
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