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Allushta [10]
2 years ago
7

"calculate the h+ in a solution that has a ph of 8.73"

Chemistry
1 answer:
alexdok [17]2 years ago
8 0
The  H+   in  a  solution  that  has  a Ph  of  8.73   is   calculate    as  follows

Ph is always =   -  log  (H+)

H+  =    10^-Ph

H+  is  therefore  =  10 ^-  8.73
H+  =  1.86  x10^-9  M
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The sodium atom loses an electron to form a sodium ion (Na+). Which statement is correct with respect to its atomic radius?
mixer [17]
Its atomic radius increases because there is less electron shielding after the sodium loses one e-.  Sodium is a nonmetal which means it forms an anion. Anions always increase from their original atomic radius
3 0
2 years ago
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If a red blood cell is 100% saturated, how many molecules of O2 are bound to it?1 billion molecules of O24 molecules of O2250 mi
kondor19780726 [428]

Answer:

1 billion molecules O₂

Explanation:

From my research, a human red blood cell contains approximately 270 million hemoglobin molecules.    

A hemoglobin molecule contains four heme groups, <em>each of which has an iron ion forming a coordination complex that carries every dioxygen molecule. </em>Therefore for each hemoglobin molecule, we will have 4 dioxygen molecules. The heme groups are responsible for the transport of every dioxygen and other diatomic gases.                    

Hence, the number of O₂ molecules in a red blood cell saturated with 100% will be:                

\frac{270 \cdot10^{6} hemoglobine molecules}{1 red blood cell} \cdot \frac{4 heme group}{1 hemoglobine molecule} \cdot \frac{1 O_{2} molecules}{1 heme group} = 1 \cdot 10^{9} O_{2} \frac{molecules}{red blood cell}

So, the correct answer is 1 billion of O₂ molecules.  

Have a nice day!

8 0
3 years ago
Consider an exceptionally weak acid, HA, with a Ka = 1x10 -20 . You make a 0.1M solution of the salt Na
Vedmedyk [2.9K]

Answer:

pH=13

Explanation:

Hello,

In this case, given the acid, we can suppose a simple dissociation as:

HA\rightleftharpoons H^+ + A^-

Which occurs in aqueous phase, therefore, the law of mass action is written by:

Ka=\frac{[H^+][A^-]}{[HA]}

That in terms of the change x due to the reaction's extent we can write:

1x10^{-20}=\frac{x*x}{0.1M-x}

But we prefer to compute the Kb due to its exceptional weakness:

Kb=\frac{Kw}{Ka}=\frac{1x10^{-14}}{1x10^{-20}}  =1x10^{-6}

Next, the acid dissociation in the presence of the base we have:

Kb=\frac{[OH^-][HA]}{[A^-]}=1x10^{6}=\frac{x*x}{0.1-x}

Whose solution is x=0.0999M which equals the concentration of hydroxyl in the solution, thus we compute the pOH:

pOH=-log([OH^-])=-log(0.0999)=1

Finally, since the maximum scale is 14, we can compute the pH by knowing the pOH:

pH+pOH=14\\\\pH=14-pOH=14-1\\\\pH=13

Regards.

5 0
3 years ago
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Brilliant_brown [7]
Number of protons as stated in the question = 92.

a. 92
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What are the rows of the periodic table of the elements also called?
lesya [120]

The rows are called Periods.

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