All categories

3 years ago

Can someone please help with this?

Physics

1 answer:

Rama09 [41]3 years ago

7 0

The last one -2.0 uc

You might be interested in

What is a list of solid mixtures in a classroom?

OLEGan [10]

Well,
1.} book
2.} computer
3.} desk
4.} chair
5.} pencil
6.} eraser
7.} dry erase board
8.} ruler
9.} calculator
10.} TV
and etc

6 0

4 years ago

Forces that act on an object but are not equal in size

mezya [45]

Forces that are equal in size but opposite in direction and do not cause a change in an object's movement are called balanced forces.

forces that aren't equal in size and do cause a change in movement (what it seems like you're asking for) are called UNBALANCED FORCES

so answer (in case that wasn't clear, as I'm tired) : unbalanced forces

7 0

3 years ago

Calculate the pressure exerted on the heel of a boy’s foot if the boy weighs 80 N and he lands on one heel,which has an area of

cricket20 [7]

Pressure at a given surface is given as ratio of normal force and area

so here force due to heel of the shoes is given as 80 N

and the area of the heel is given as 16 cm^2

so we can say

$P = \frac{F}{A}$

here we have

F = 80 N

$A = 16 cm^2 = 16 * 10^{-4} m^2$

$P = \frac{80}{16 * 10^{-4}}$

$P = 5 * 10^4 N/m^2$

so pressure at the surface due to its heel will be 5 * 10^4 N/m^2

3 0

3 years ago

Upthrust given by Water to the body

erica [24]

Answer:

According to Archimedes principle the upthrust on the body is equal to the weight of the water displaced by the body. ... Here, the mass would be the net difference in the weight of the object.

7 0

3 years ago

A scene in a movie has a stuntman falling through a floor onto a bed in the room below. The plan is to have the actor fall on hi

IgorC [24]

Answer:

$m=17.79Kg$

Explanation:

In this process energy must be conserved. On the initial stage, there will be only gravitational potential energy, while on the final stage there will be only elastic potential energy, so they will be equal. We write this as:

$U_g=U_e$

Which is the same as:

$mgh=\frac{k \Delta x^2}{2}$

So we can obtain our mass from there, and for our values:

$m=\frac{k \Delta x^2}{2gh}=\frac{(65144 N/m)(0.1333m)^2}{2(9.8m/s^2)(3.32m)}=17.79Kg$

4 0

3 years ago