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Nookie1986 [14]
3 years ago
13

Can someone please help with this?

Physics
1 answer:
Rama09 [41]3 years ago
7 0
The last one -2.0 uc
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4
telo118 [61]
Ik what it is hit me up for it
5 0
3 years ago
Which object will have greater acceleration? Why?​
dexar [7]

Answer:

Object D

Explanation:

Use Newton's Second Law to determine the acceleration that each object has.

  • F = ma

The force applied in both cases is 50 N, but the mass for object C and object D is different.

Let's start with object C first:

  • F = ma
  • 50 N = 10 kg · a
  • 50 = 10a
  • 5 = a

The acceleration object C undergoes is 5 m/s².  

Now let's calculate object D next:

  • F = ma
  • 50 N = 2 kg * a
  • 50 = 2a
  • 25 = a

The acceleration object D undergoes is 25 m/s².

Object D has greater acceleration because it has a smaller mass. The object with a smaller mass will accelerate more in order to satisfy Newton's 2nd Law.

7 0
3 years ago
Does frequency affect wavelength?
Vinil7 [7]

Answer:

yeah

Explanation:

as wavelength increases frequency decreases and it goes the same for the opposite way

6 0
3 years ago
What part of the atmosphere contains dust, water vapor, and 75% of all gases
Alexeev081 [22]

Answer:

Troposphere

Explanation:

Our atmosphere yay

7 0
3 years ago
Read 2 more answers
The sun rotates once in 25.05 days. That is 601.2 hours. so the sun's rotational speed is 0.0017 rotations per hour. what is the
Margaret [11]

Answer:

v=2019.09\ m.s^{-1}

Explanation:

Given:

  • time taken by the sun to complete one revolution, t=601.2\ hr
  • radial distance of the sunspot, r=6.955\times 10^8\ m.s^{-1}

<u>Therefore, angular speed of rotation of sun:</u>

\omega=\frac{2\pi}{601.2\times 3600} \ rad.s^{-1}

<u>Now the tangential velocity of the sunspot can be given by:</u>

v=r.\omega

v=6.955\times 10^8\times \frac{2\pi}{601.2\times 3600}

v=2019.09\ m.s^{-1}

4 0
3 years ago
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