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ELEN [110]
3 years ago
9

How does conduction occur?

Physics
1 answer:
Mamont248 [21]3 years ago
4 0
In the case of metal, it comtains delocalised electrons which can move freely throughout the metal. when heat is applied to one end of the metal, the atoms and delocalised electrons gain more kinetic energy and move faster and they hit the neighbouring atoms more and heat is transfer theoughout the matal through conduction.
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If I bought 59 kids off the black market in a secret door in the stalls and I sell 21 kids then ask for 81 more then 12 off the
larisa [96]

You will be left with 106 kids

<h3>Meaning of word problem</h3>

A word problem can be defined as a mathematical problem that is written in word or written in a sentence format.

In a word problem, the student is expected to decode the sentence into a mathematical expression before solving

In conclusion, You will be left with 106 kids

Learn more about word problems: brainly.com/question/13818690

#SPJ1

5 0
2 years ago
Ella has a mass of 56 kg, and Tyrone has a mass of 68 kg. Ella is standing at the top of a skateboard ramp that is 1.5 meters ta
Ivahew [28]

Answer:Tyrone is 12 more kg more than Ella.

Explanation:

7 0
3 years ago
Read 2 more answers
What is the mechanical advantage of an inclined plane that has a length of 9 feet and a height of 3 feet?
Rainbow [258]

Answer:

it would be 3

Explanation:

because you have to divide the length by the height of the incline.

5 0
3 years ago
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A system undergoes a two-step process. In the first step, the internal energy of the system increases by 222 J when 150 J of wor
joja [24]

Answer:0 J

Explanation:

Given

For first step

change in internal Energy of the system is \Delta U_1=222 J

Work done on the system W_1=-150 J

For second step

change in internal Energy of the system is \Delta U_2=123 J

Work done on the system W_2=-195 J

Work done on the system is considered as Positive and vice-versa.

and from first law of thermodynamics

Q=\Delta U+W

for first step

Q_1=222-150=72 J

Q_2=123-195=-72 J

overall heat added=Q_1+Q_2

Q_{net}=72-72 =0

For overall Process Heat added is 0 J

8 0
3 years ago
Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B , with a mass of 8.0 kg, is moving in the opposi
Anon25 [30]
Consider velocity to the right as positive.

First mass:
m₁ = 4.0 kg
v₁ = 2.0 m/s to the right

Second mass:
m₂ = 8.0 kg
v₂ = -3.0 m/s to the left

Total momentum of the system is
P = m₁v₁ + m₂v₂
   = 4*2 + 8*(-3)
  = -16 (kg-m)/s

Let v (m/s) be the velocity of the center of mass of the 2-block system.

Because momentum of the system is preserved, therefore
(m₁+m₂)v= -16
(4+8 kg)*(v m/s) = -16 (kg-m)/s
v = -1.333 m/s

Answer:
The center of mass is moving at 1.33 m/s to the left.
5 0
3 years ago
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