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3 years ago

Forces that act on an object but are not equal in size

1 answer:

7 0

Forces that are equal in size but opposite in direction and do not cause a change in an object's movement are called balanced forces.

forces that aren't equal in size and do cause a change in movement (what it seems like you're asking for) are called UNBALANCED FORCES

so answer (in case that wasn't clear, as I'm tired) : unbalanced forces

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Give reasons: A freely suspended magnet shows N-S poles at rest.

aniked [119]

Answer:

A freely suspended magnet comes to rest along the N-S direction.

Explanation:

-Irrespective of direction of suspension, the bar eventually comes to rest at earth's N-S direction.

-Bar end that points to Earth's north is called the North Pole. Bar end that point's to earth's south is called the South pole.

-The reason for this default positioning is called the Directive Property. This is because earth acts as an external magnetic field.

7 0

4 years ago

What is the charge on an object that has 1.09x10^13 excess electrons?

Nadya [2.5K]

Answer:

$-1.74\cdot 10^{-6} C$

Explanation:

The electron is the particle that rotates around the nucleus of the atom; it has a negative electric charge equal to :

$e=-1.6\cdot 10^{-19}C$

which is known as fundamental charge.

For an object containing N excess electrons, the total charge of the object is

$Q=Ne$

In this problem, the number of excess electrons in the object is:

$N=1.09\cdot 10^{13}$

Therefore, by plugging it the numbers, we can find the value of Q, the total charge of the object:

$Q=(1.09\cdot 10^{13})(-1.6\cdot 10^{-19})=-1.74\cdot 10^{-6} C$

5 0

4 years ago

Matt is driving down 7th street. He drives 150 meters in 18 seconds. Assuming he does not speed up or slow down, what is his spe

Olin [163]

(150 meters) / (18 seconds) = 8.33 meters per second

4 0

4 years ago

Como anticipan la caída del proyectil, con movimiento parabólico para que el misil no haga daño

Elena L [17]

Answer:

Conociendo la velocidad inicial del proyectil y el angulo de lanzamiento con respecto ala horizontal.

Explanation:

Para poder anticipar la caída del proyectil es importante conocer la velocidad inicial del proyectil y el angulo de disparo del proyectil con respecto a la horizontal.

A continuación se presenta un diagrama o esquema donde se pueden ver estas variables y se explicaran a la brevedad:

Para poder encontrar el rango que es la máxima distancia horizontal recorrida por el proyectil debemos utilizar la siguiente ecuación:

$x=(v_{o})_{x} *t\\where:\\(v_{o})_{x} = velocidad inicial x-component [m/s]\\t= time [s]$

Para poder encontrar el tiempo debemos utilizar la siguiente ecuación:

$y=(v_{y} )_{o}*t-0.5*g*t^{2} \\donde:\\(v_{y} )_{o}= velocidad inicial componente y [m/s]\\g = gravity = 9.81 [m/s^2]\\t = time [s]$

En la anterior ecuación, igualamos y = 0, ya que cuando el proyectil cae al suelo la distancia vertical es cero. De esta manera podemos encontrar el tiempo t, ya que conocemos la velocidad inicial del proyectil en la componente y.

Seguidamente reemplazamos t en la primera ecuacion y encontramos la distancia x o el rango.

8 0

4 years ago

What travels faster, light or sound?

Allushta [10]

Answer:

light travels faster than sound

4 0

3 years ago

Read 2 more answers