The possible magnitude for the force of static friction on the stationary cart is 72.1 N.
The given parameters:
- <em>Applied force on the cart, F = 72.1 N</em>
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Based on Newton's second law of motion, the force applied to object is directly proportional to the product of mass and acceleration of the object.
F = ma
Static frictional force is the force resisting the motion of an object at rest.
where;
is the frictional force
Thus, the possible magnitude for the force of static friction on the stationary cart is 72.1 N.
Learn more about Newton's second law of motion: brainly.com/question/25307325
Answer:
Distance = 13.9 meters
Explanation:
Given the following data;
Maximum speed = 150 km/hr to meters per seconds = 150 * 1000/3600 = 41.67 m/s
Decelerating speed = 3m/s
To find the distance travelled with this speed;
Distance = maximum speed/decelerating speed
Distance = 41.67/3
Distance = 13.9 meters
Therefore, the bus would travel a distance of 13.9 meters before stopping.
For this we use general equation for gases. Our variables represent:
p- pressure
v-volume
t- temperature
P1V1/T1 = P2V2/T2
in this equation we know:
P1,V1 and T1, T2 and V2.
We have one equation and 1 unknown variable.
P2 = T2P1V1/T1V2 = 1.1atm
Unbalanced. _______ and not equal. in not sure about the 2nd choice from the info im looking at. the balanced version is 2NaOH<span> + </span><span>H2SO4</span><span> = </span><span>Na2SO4</span><span> + </span>2<span>H2O
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